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    <p><code>#tap</code> is a method that basically "passes along" the block to the next. It isn't supposed to "change" the flow of the method. For example</p> <p><a href="http://ruby-doc.org/core-2.0/Object.html#method-i-tap" rel="nofollow">http://ruby-doc.org/core-2.0/Object.html#method-i-tap</a></p> <pre><code>(1..10) .tap {|x| puts "original: #{x.inspect}"} .to_a .tap {|x| puts "array: #{x.inspect}"} .select {|x| x%2==0} .tap {|x| puts "evens: #{x.inspect}"} .map { |x| x*x } .tap {|x| puts "squares: #{x.inspect}"} </code></pre> <p>It's sort of like a unix pipe, but has a chance to access the data as it goes along. like a tap.</p> <p>It is supposed to take something and return the same thing to the next part of the pipe.</p> <p>However, using <code>break a</code> will <strong>break out</strong> of the tap, and <strong>return a</strong>. That is, instead of returning what <code>#tap</code> would normally return (the same thing that it got), it would return <code>a</code> instead.</p> <p>The use of <code>#tap</code> in this case is to pass values down the pipe "as normal", <strong>except</strong> when <code>version</code> is true; in that case it will send along <code>o.send(version)</code> instead.</p> <p>Basically, the normal flow is</p> <pre><code>object.send(attribute_name).send('url') </code></pre> <p>and with <code>tap</code>, it's normally "unchanged". However, using <code>break o.send(version)</code>, the flow is then instead</p> <pre><code>intermediate = object.send(attribute_name); if version return intermediate.send(version).send('url'); # ignore the result of intermediate # and replace it with o.send(version) else return intermediate.send('url'); # maintain normal flow...it's like nothing # was ever tapped end </code></pre>
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    1. POWhat does "break" do in this ruby statement
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    1. USMathieu Mahé
    1. USJustin L.
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    1. COThis is correct but I can't accept all answers so I chose @kajics but thanks anyway.
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      1. USPeter Andersson
 

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