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    <p>You can do this by making a custom <code>JsonConverter</code> which will handle rounding (or discarding) the decimal values. It might look something like this:</p> <pre><code>class CustomIntConverter : JsonConverter { public override bool CanConvert(Type objectType) { return (objectType == typeof(int)); } public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer) { JValue jsonValue = serializer.Deserialize&lt;JValue&gt;(reader); if (jsonValue.Type == JTokenType.Float) { return (int)Math.Round(jsonValue.Value&lt;double&gt;()); } else if (jsonValue.Type == JTokenType.Integer) { return jsonValue.Value&lt;int&gt;(); } throw new FormatException(); } public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer) { throw new NotImplementedException(); } } </code></pre> <p>You can then use the custom converter like this:</p> <pre><code>JsonSerializerSettings settings = new JsonSerializerSettings { Converters = new List&lt;JsonConverter&gt; { new CustomIntConverter() } }; string json = @"[2.6, 0, 4.1, 5, -3, -2.2]"; List&lt;int&gt; list = JsonConvert.DeserializeObject&lt;List&lt;int&gt;&gt;(json, settings); foreach (int val in list) { Console.WriteLine(val); } </code></pre> <p>The output of the above would be this:</p> <pre><code>3 0 4 5 -3 -2 </code></pre> <p>If you would rather the converter ignore decimal values rather than round them, replace the following line of code</p> <pre><code> return (int)Math.Round(jsonValue.Value&lt;double&gt;()); </code></pre> <p>with this:</p> <pre><code> return (existingValue ?? default(int)); </code></pre> <p>After making that change, the output of the test code above would then look like this:</p> <pre><code>0 0 0 5 -3 0 </code></pre>
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