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    <p>Using your example:</p> <pre><code>$foo = new Person; $foo-&gt;name = 'smith'; $something = doSomething($foo); echo $something; </code></pre> <p>Type hinting means that whatever you pass must be an instance of (the same type as) the type you're hinting.</p> <p>So, if you hint to <code>Person</code> only objects of that type will be accepted.</p> <p>In the example you gave, you tried to pass a string instead of an object.</p> <p><strong>Update</strong></p> <p>"Type hinting" forces you to only pass objects of a particular type. This prevents you from passing incompatible values, and creates a standard if you're working with a team etc.</p> <p>So, let's say you have a function <code>sing()</code>. You want to be sure that it will only accept objects of type <code>Song</code>.</p> <p>Let's create our class <code>Song</code>:</p> <pre><code>class Song{ public $title; public $lyrics; } </code></pre> <p>and our function sing(). We will type hint to <code>Song</code> to ensure that no other type of params can be passed to it:</p> <pre><code>function sing(Song $song){ echo "Singing the song called " .$song-&gt;title; echo "&lt;p&gt;" . $song-&gt;lyrics . "&lt;/p&gt;"; } </code></pre> <p>Now, again, the function can ONLY accept objects of type <code>Song</code> because that's what we hinted to in the declaration (<code>Song $song</code>).</p> <p>Let's create a Song and pass it:</p> <pre><code>$hit = new Song; $hit-&gt;title = "Beat it!"; $hit-&gt;lyrics = "It doesn't matter who's wrong or right... just beat it!"; </code></pre> <p>then we call:</p> <pre><code>sing($hit); </code></pre> <p>Which will work just fine.</p> <p>Now, let's say we have a class <code>Poem</code>:</p> <pre><code>class Poem{ public $title; public $lyrics; } $poem = new Poem; $poem-&gt;title = "Look at the sea"; $poem-&gt;lyrics = "How blue, blue like the sky, in which we fly..." </code></pre> <p>If we try to call it using our function 'sing';</p> <pre><code>sing($poem) </code></pre> <p>we will get an error because <code>$poem</code> is not the type of object we've hinted to when creating the function <code>sing()</code>.</p>
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    1. CO@Exploit You have to instantiate the object before passing it. That's why you're getting the error - you just passed a string. Type hinting doesn't turn the param you pass into an object.
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    2. COWhy the down vote?
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    3. COsorry about the votedown my finger clicked on the mouse and i wasnt able to put it back to zero. I'm going to try another sample on my computer and will post an update. For some reason when i try it myself I keep getting errors. If you dont mind can you post a working sample in an answer? maybe it will help me better understand. thanks
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