StackOverflow2013

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17665103
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0
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2013-07-15T22:38:24.407
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2013-07-15T22:38:24.407
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1919155
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Taking this section as an example, it can be greatly simplified: <pre><code> Block(const QPixmap &img = Pixmap(), QObject *parent = 0); Block(const QPoint &pos, const QPixmap &img = Pixmap(), QObject *parent = 0); Block(int x, int y, const QPixmap &img = Pixmap(), QObject *parent = 0); </code></pre> Remove these two: <pre><code> Block(const QPixmap &img = Pixmap(), QObject *parent = 0); Block(int x, int y, const QPixmap &img = Pixmap(), QObject *parent = 0); </code></pre> If you want it at "no position", you just give it an empty <code>QPoint</code>: <pre><code> Block(QPoint(), img); </code></pre> And if you want it at <code>x, y</code>, then make a <code>QPoint(x, y)</code> <pre><code> Block(QPoint(x, y), img, parent); </code></pre> (You could of course make it <code>QPoint pos = QPoint()</code>, so that if you want an empty one you can use <code>Block()</code>. The same principle can be applied to <code>Rect</code>, you have several variants that are "nearly the same". Replace all the variations with one that takes a QRect as the first argument. If you don't happen to "have" a QRect, surely one can be created as a temporary (and in most cases, that will just "disappear"). Hopefully, this ALSO makes the set actual constructor simpler, since you can just do <pre><code>m_rect = rect; </code></pre> rather than having to write 6 different forms of "I have some different items, that need to be made into a rect". Unless there is a VERY good reason to add another constructor, don't. Just because the code you are working on right now happens to have <code>x</code>, <code>y</code>, <code>h</code>, and <code>w</code>, doesn't mean you can't make it into a <code>QRect</code> pretty easily. 
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1. PORule of thumb for C++ constructor overloads?
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1. PTAnswer
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1. USMats Petersson
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