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    <p>@JHaasie77 has a good approach, use the <code>candidate_no</code> as an orderer (which then comes down to an alpha-numeric sort order) making 9 first when you use descending order. (likewise, C9 would be last if you used ascending order). If there's no further disqualifiers, then that's the easiest route.</p> <p>If you're making the order decision based on another metric, you probably want to change your table around to add some other column(s) you can order by. (Maybe it's by the "home-town hero" vs the "visitor", or by age with youngest matches first--who knows.) But any other detail would need to be added to the database so you could then use it to create a preference in the result.</p> <p>with that said, you can slim down that query a bit by using a <code>GROUP BY</code> instead of union. this also makes it dynamic enough that if you had more candidates in the future, the query would automatically re-adjust. So, your long query now becomes:</p> <pre><code>SELECT sum ,candidate_no ,@curRank := @curRank + 1 AS rank FROM ( SELECT SUM(score) / 5 SUM ,candidate_no FROM SCORE GROUP BY candidate_no ) a , ( SELECT @curRank := 0 ) r ORDER BY sum DESC ,candidate_no DESC </code></pre> <p>Which basically means that for every unique <code>candidate_num</code> it will sum the score and divide by 5. The above also adds the second orderer for <code>candidate_num</code> making <code>C9</code> appears first <a href="http://www.sqlfiddle.com/#!2/9b20b/5/0" rel="nofollow">as seen here</a>.</p>
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    1. POHow can I break the tie from my MySQL query using PHP?
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    1. USBrad Christie
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    1. POHow can I break the tie from my MySQL query using PHP?
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    1. COThanks so much. It helped me.
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      1. USbaikoko09
 

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