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POUnable to retrieve latest pic from PHP
 

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  1. POUnable to retrieve latest pic from PHP
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    <p>I am using following code to store images on my webserver:</p> <pre><code>function SavePic() { $allowedExts = array("jpeg", "jpg"); $temp = explode(".", $_FILES["UserPic"]["name"]); $extension = end($temp); if ((($_FILES["UserPic"]["type"] == "image/jpeg") || ($_FILES["UserPic"]["type"] == "image/jpg")) //&amp;&amp; ($_FILES["UserPic"]["size"] &lt; 2097152) &amp;&amp; in_array($extension, $allowedExts)) { if ($_FILES["UserPic"]["error"] &gt; 0) { echo json_encode("Error: ".$_FILES["UserPic"]["error"]); } else { $folder = "/home5/username/public_html/Project/Users/Images/"; echo move_uploaded_file($_FILES["UserPic"]["tmp_name"],$folder.$_REQUEST["email"].".".$extension); } } else { echo json_encode("Invalid file"); } } </code></pre> <p>And Following code to retrieve image:</p> <pre><code>function RetrievePic() { $handle = fopen('php://input','r'); $jsonInput = fgets($handle); // Decoding JSON into an Array $retrieveParameters = json_decode($jsonInput,true); $UserPic = array("UserPic" =&gt; "http://www.mysite.com/Project/Users/Images/".$retrieveParameters['email']."."."jpg"); echo json_encode($UserPic); } </code></pre> <p>For Example if my email is abc@xyz.com then image will be stored as "abc@xyz.com.jpg". The problem is that when I try to overwrite image in order to replace old one with new one, server is returning old one everytime.</p> <p><strong>Update:</strong> When I place url in browser e.g <a href="http://www.mysite.com/Project/Users/Images/abc@xyz.com.jpg" rel="nofollow">http://www.mysite.com/Project/Users/Images/abc@xyz.com.jpg</a> latest image is shown and after that I start receiving latest image.</p>
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    1. USdakshbhatt21
    1. USAli Shahid
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    1. COYou might want to look at how the webserver is caching your data, you can always add a timestamp to the url (maybe file modified time?) `http://www.mysite.com/Project/Users/Images/abc@xyz.com.jpg?modifiedtime`
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      1. UShank
    2. COJust like @hank has just written: try `$UserPic = array("UserPic" => "http://www.mysite.com/Project/Users/Images/".$retrieveParameters['email']."."."jpg?".time());`
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      1. USMarcin Krawiec
    3. CO@MarcinKrawiec using `time()` will force a reload every time, which is a waste of bandwidth, better to use the actual modified time of the file.
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