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POfind center of circle when three points are given
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17550089
data
AcceptedAnswerId
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AnswerCount
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ClosedDate
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CommunityOwnedDate
CreationDate
2013-07-09T13:54:40.630
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2017-10-10T18:14:04.547
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2017-10-10T18:14:04.547
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Body
I studied <a href="http://mathforum.org/library/drmath/view/55239.html" rel="nofollow noreferrer">this link</a> and coded accordingly but getting Wrong Answer for the example explained in the link, During solving the equation, I subtracted equation 2 from equation 1 and equation 3 from equation 2 and then proceed further. Please check link for clarification. My code is: <pre><code>include<stdio.h> int is_formCircle(float a1,float b1,float a2,float b2,float a3,float b3) { float p1=a2-a1; float p2=a3-a2; float p3=b2-b1; float p4=b3-b2; float alpha=(a1+a2)*(a1-a2) + (b1+b2)*(b1-b2); float beta =(a2+a3)*(a2-a3) + (b2+b3)*(b2-b3); float y1=p1*beta - p2*alpha; float y2=p2*p3 - p1*p4; if(y2==0 || y1==0) return 1; float y=y1/y2; float x1 = 2*p4*y + beta; float x2 = 2*p2; float x = x1/x2; printf("x=%f y=%f\n",x,y); return 0; } int main() { float a1,a2,a3,a4,b1,b2,b3,b4; a1=4.0; b1=1.0; a2=-3.0; b2=7.0; a3=5.0; b3=-2.0; is_formCircle(a1,b1,a2,b2,a3,b3); return 0; } </code></pre> MY another Code: <pre><code>#include<stdio.h> int is_formCircle(float a1,float b1,float a2,float b2,float a3,float b3) { float mid1,mid2,mid3,mid4,m1,m2,D,Dx,Dy,x,y; mid1 = a1+(a2-a1)/2; mid2 = b1+(b2-b1)/2; mid3 = a2+(a3-a2)/2; mid4 = b2+(b3-b2)/2; m1=(b2-b1)/(a2-a1); m2=(b3-b2)/(a3-a2); m1=-1*m1; m2=-1*m2; D=m2-m1; Dx=mid2-(m1*mid1) + (mid3*m2) - mid4; Dy=(m1*(mid3*m2-mid4))-(m2*(mid1*m1-mid2)); x=Dx/D; y=Dy/D; printf("%f %f",x,y); return 0; } int main() { float a1,a2,a3,b1,b2,b3; a1=4.0; b1=1.0; a2=-3.0; b2=7.0; a3=5.0; b3=-2.0; is_formCircle(a1,b1,a2,b2,a3,b3); return 0; } </code></pre> Why my code giving Wrong Answer?
Tags
<algorithm><math><linear-equation>
Title
find center of circle when three points are given
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