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    <p>There is currently no such concept implemented in oscP5. Here is a similar <a href="https://stackoverflow.com/questions/5566285/processing-oscp5-library">discussion</a>.</p> <p>Seems like you have to build something yourself based on the memory address found in the debug info, e.g. <code>### new Client @ netP5.TcpClient@164b9b6</code>. I scan the System.out stream for the string <code>new Client</code> and call the method <code>clientConnected</code> then. This is totally hacky, but I currently don’t see another way.</p> <pre><code>import java.io.PrintStream; import oscP5.*; import netP5.*; OscP5 oscP5tcpServer; OscP5 oscP5tcpClient; NetAddress myServerAddress; void setup() { // overwrite standard System.out System.setOut(new PrintStream(System.out) { public void println(String s) { if(s.indexOf("new Client") != -1){ clientConnected(getMemoryAddress(s)); } super.println(s); } // override some other methods? }); oscP5tcpServer = new OscP5(this, 11000, OscP5.TCP); oscP5tcpClient = new OscP5(this, "127.0.0.1", 11000, OscP5.TCP); } void clientConnected(int memoryAddress){ println("Client connected, with memory address " + memoryAddress); } int getMemoryAddress(String s){ return Integer.parseInt(s.substring(s.lastIndexOf('@')+1), 16); } void draw() { } void mousePressed() { oscP5tcpClient.send("/test", new Object[] {new Integer(1)}); } void keyPressed() { println(oscP5tcpServer.tcpServer().getClients().length); } void oscEvent(OscMessage theMessage) { System.out.println("### got a message " + theMessage); if(theMessage.checkAddrPattern("/test")) { OscMessage m = new OscMessage("/response"); m.add("server response: got it"); oscP5tcpServer.send(m,theMessage.tcpConnection()); } } </code></pre>
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    1. POHow to listen for tcp changes using OscP5?
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    1. POHow to listen for tcp changes using OscP5?
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    1. COI think I know what you mean, I've updated the question with my current code, which does the job, but is not very elegant. Another option would be for the clients to send a connect/disconnect message. I was just wondering if there a clean/less hacky way to do this
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      1. USGeorge Profenza
    2. COStill hacky, but probably a bit more efficient than what I have (+1) :)
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      1. USGeorge Profenza
 

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