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POBASH - Refer to parameters using variable
 

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    <p>I was trying to make a small script that calculates a binary number to decimal. It works like this:</p> <p>-Gets '1' or '0' digits as SEPARATE parameters. e.g. "./bin2dec 1 0 0 0 1 1 1".</p> <p>-For each parameter digit: if it is '1', multiplies it with the corresponding power of 2 (in the above case, the most left '1' will be 64), then adds it in a 'sum' variable.</p> <p>Here's the code (it is wrong in the noted point):</p> <pre><code> #!/bin/bash p=$((2**($#-1))) #Finds the power of two for the first parameter. sum=0 #The sum variable, to be used for adding the powers of two in it. for (( i=1; i&lt;=$#; i++ )) #Counts all the way from 1, to the total number of parameters. do if [ $i -eq 1 ] # *THIS IS THE WRONG POINT* If parameter content equals '1'... then sum=$(($sum+$p)) #...add the current power of two in 'sum'. fi p=$(($p/2)) #Divides the power with 2, so to be used on the next parameter. done echo $sum #When finished show the 'sum' content, which is supposed to be the decimal equivalent. </code></pre> <p>My question is in the noted point (line #10, including blank lines). There, I’m trying to check if EACH parameter's content equals 1. How can I do this using a variable? </p> <p>For example, $1 is the first parameter, $2 is the 2nd and so on. I want it to be like $i, where 'i' is the variable that is increased by one each time so that it matches the next parameter.</p> <p>Among other things, I tried this: '$(echo "$"$i)' but didn't work.</p> <p>I know my question is complicated and I tried hard to make it as clear as I could. Any help?</p>
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    1. COJust a side note: bash can make the conversion like this --> `$ printf '%d\n' "$((2#1000111))"` which returns 71.
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    2. CO@fedorqui or just `echo $((2#1000111))`
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    3. COIkr, I just wanted a script which uses that way I did above. And to find out if and how can we refer to a parameter using a variable.
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