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POCrypto RSA in Python
 

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    <p>I am checking a code written in Python which is used to generate an RSA public private key pair.</p> <p>It generates the keypair however, at the end of the code it runs ssh-keygen again. I am not sure why that is done. Since, RSA.generate() will itself generate the keypair that we export into two separate files. Why is there a need to run ssh-keygen again?</p> <p>Here are few lines from the code:</p> <pre><code>keypair = RSA.generate(1024, randfunc) with open("pub", "w") as pubfile, open("id_rsa", "w") as privfile: privfile.write(keypair.exportKey()) pubfile.write(keypair.publickey().exportKey()) system("ssh-keygen -m PKCS8 -i -f pub &gt; id_rsa.pub &amp;&amp; rm pub") </code></pre> <p>the file <strong>pub</strong> will store the public key and <strong>id_rsa</strong> will store the private key from the keypair generated by RSA.generate() function.</p> <p>Now, why is it running the ssh-keygen command at the end?</p> <p>Also, it does not take any input file for the -i parameter and -f parameter takes the name pub which was the public key already generated.</p> <p>After executing the code I get two files, id_rsa and id_rsa.pub</p> <p>id_rsa is the private key generated using RSA.generate() but id_rsa.pub stores the result of ssh-keygen command.</p> <p>I need some help to understand the reason for invoking ssh-keygen at the end of the script and also the parameters passed to ssh-keygen. -i should be passed some value and also -f should have output filename and not input.</p> <p><strong>Note:</strong> I read that this is done to convert the public key from OpenSSL format to OpenSSH format using ssh-keygen so that it starts with ssh-rsa instead of BEGIN PUBLIC KEY.</p> <p>Does that mean the format of corresponding private key should also be changed?</p> <p>Since it starts with,</p> <p>BEGIN PRIVATE KEY</p>
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