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POHow to parse same name tag in Android XML DOM Parsing
 

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  1. POHow to parse same name tag in Android XML DOM Parsing
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    <p>I am not able to parse my XML here.It returns "Item" only.<br> My AndroidActivity cannot be shown as it is very big that's why i have only shown the part which is responsible for parsing.</p> <p>My XML Looks like this :</p> <pre><code>&lt;MyResource&gt; &lt;Item&gt;First&lt;/Item&gt; &lt;Item&gt;Second&lt;/Item&gt; &lt;/MyResource&gt; </code></pre> <p>My ActivityClass method:</p> <pre><code>public class ShowItems extends Activity{ ListView lv; ListAdapter adapter; static final String KEY_RESOURCE = "MyResource"; // parent node static final String KEY_ITEM = "Item"; ArrayList&lt;HashMap&lt;String, String&gt;&gt; mylist = new ArrayList&lt;HashMap&lt;String, String&gt;&gt;(); String[] from={KEY_ITEM }; int[] to={R.id.mylist_item}; @Override protected void onCreate(Bundle savedInstanceState) { // TODO Auto-generated method stub super.onCreate(savedInstanceState); setContentView(R.layout.showitems); lv=(ListView) findViewById(R.id.lv_items); parseXML(); adapter = new SimpleAdapter(this, mylist,R.layout.list_item,from , to); lv.setAdapter(adapter); } private void parseXML() { // TODO Auto-generated method stub XMLParser parser = new XMLParser(); final String URL="http://10.0.2.2:8080/MySite/xml"; String xml = parser.getXmlFromUrl(URL); Document doc = parser.getDomElement(xml); NodeList nl = doc.getElementsByTagName(KEY_RESOURCE); for (int i = 0; i &lt; nl.getLength(); i++) { HashMap&lt;String, String&gt; map = new HashMap&lt;String, String&gt;(); Element e = (Element) nl.item(i); map.put(KEY_ITEM, parser.getValue(e, KEY_ITEM)); mylist.add(map); } } </code></pre> <p>My XML Parser Class:</p> <pre><code>import java.io.IOException; import java.io.StringReader; import java.io.UnsupportedEncodingException; import javax.xml.parsers.DocumentBuilder; import javax.xml.parsers.DocumentBuilderFactory; import javax.xml.parsers.ParserConfigurationException; import org.apache.http.HttpEntity; import org.apache.http.HttpResponse; import org.apache.http.client.ClientProtocolException; import org.apache.http.client.HttpClient; import org.apache.http.client.methods.HttpGet; import org.apache.http.impl.client.DefaultHttpClient; import org.apache.http.util.EntityUtils; import org.w3c.dom.Document; import org.w3c.dom.Element; import org.w3c.dom.Node; import org.w3c.dom.NodeList; import org.xml.sax.InputSource; import org.xml.sax.SAXException; import android.util.Log; public class XMLParser { public String getXmlFromUrl(String url) { String xml = null; try { HttpClient httpClient = new DefaultHttpClient(); HttpGet httpGet = new HttpGet(url); HttpResponse httpResponse = httpClient.execute(httpGet); HttpEntity httpEntity = httpResponse.getEntity(); xml = EntityUtils.toString(httpEntity); } catch (UnsupportedEncodingException e) { e.printStackTrace(); } catch (ClientProtocolException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } return xml; } public Document getDomElement(String xml){ Document doc = null; DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); try { DocumentBuilder db = dbf.newDocumentBuilder(); InputSource is = new InputSource(); is.setCharacterStream(new StringReader(xml)); doc = db.parse(is); } catch (ParserConfigurationException e) { Log.e("Error: ", e.getMessage()); return null; } catch (SAXException e) { Log.e("Error: ", e.getMessage()); return null; } catch (IOException e) { Log.e("Error: ", e.getMessage()); return null; } // return DOM return doc; } public String getValue(Element item, String str) { NodeList n = item.getElementsByTagName(str); return this.getElementValue(n.item(0)); } public final String getElementValue( Node elem ) { Node child; if( elem != null){ if (elem.hasChildNodes()){ for( child = elem.getFirstChild(); child != null; child = child.getNextSibling() ){ if( child.getNodeType() == Node.TEXT_NODE ){ return child.getNodeValue(); } } } } return ""; } } </code></pre> <p>I am not able to parse my XML here.What is the problem here ?<br> It returns "Item" only.<br> What do i need to do in my ActivityClass specially in this part of the code :</p> <pre><code>String xml = parser.getXmlFromUrl(URL); Document doc = parser.getDomElement(xml); NodeList nl = doc.getElementsByTagName(KEY_RESOURCE); for (int i = 0; i &lt; nl.getLength(); i++) { HashMap&lt;String, String&gt; map = new HashMap&lt;String, String&gt;(); Element e = (Element) nl.item(i); map.put(KEY_ITEM, parser.getValue(e, KEY_ITEM)); mylist.add(map); } </code></pre>
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    1. COI am not sure what you want here, can you please be more clear?
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      1. USkosa
    2. COyou see his XML. He has two `<Item>` tags that he need to parse through DOM. And When he parse it through the above described method only the first `<Item>` tag is parsed the other (or the reamaining ones) are ignored.
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      1. POHow to parse same name tag in Android XML DOM Parsing
      1. USAltair
    3. CO@AltairRules: 1) Are you getting "First" (or) "Second" as input? 2) Could you print and see size of NodeList nl = doc.getElementsByTagName(KEY_RESOURCE);?
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