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17395267
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2013-06-30T22:02:05.063
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2013-06-30T22:10:28.617
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2017-05-23T11:56:31.167
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After <a href="https://stackoverflow.com/users/985241/rmagnum2002">rmagnum2002</a> made me realize that I could use foreign_key parameter here, I started googling "rails multiple foreign key to same table", stumbled upon a bunch of outdated SO answers that didn't work and finally found <a href="http://www.emreakkas.com/ruby-on-rails/rails-multiple-columns-to-the-same-tables-key" rel="nofollow noreferrer">this article</a> which helped me write the code that works. So, this is the relation that I put into my JSymbol model: <pre><code>belongs_to :created_by, :class_name => User, :foreign_key => "created_by_id" belongs_to :updated_by, :class_name => User, :foreign_key => "updated_by_id" </code></pre> and this one is from Users model: <pre><code>has_many :occurances_as_created_by, :class_name => JSymbol, :foreign_key => "created_by_id" has_many :occurances_as_updated_by, :class_name => JSymbol, :foreign_key => "updated_by_id" </code></pre> I didn't have to add anything in my action method, and this is what I put in the view: <pre><code><%= j_symbol.created_by.username %> <%= j_symbol.updated_by.username %> </code></pre> This is what happens in SQL if anyone is interested (which means it actually does it through separate select queries instead of joins so I might yet keep looking for a better solution): <pre><code>JSymbol Load (0.3ms) SELECT "j_symbols".* FROM "j_symbols" JSymbolType Load (0.3ms) SELECT "j_symbol_types".* FROM "j_symbol_types" User Load (0.5ms) SELECT "users".* FROM "users" WHERE "users"."id" = 7 LIMIT 1 User Load (0.4ms) SELECT "users".* FROM "users" WHERE "users"."id" = 8 LIMIT 1 CACHE (0.0ms) SELECT "users".* FROM "users" WHERE "users"."id" = 8 LIMIT 1 CACHE (0.0ms) SELECT "users".* FROM "users" WHERE "users"."id" = 8 LIMIT 1 Rendered j_symbols/index.html.erb within layouts/j_symbols (7.8ms) CACHE (0.0ms) SELECT "users".* FROM "users" WHERE "users"."id" = 8 LIMIT 1 </code></pre>
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