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POPlot a 3D surface from {x,y,z}-scatter data in python
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2013-06-28T14:50:14.490
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2013-06-28T16:53:29.580
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2013-06-28T16:31:45.230
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I'm trying to plot a 3D surface constructed to fit some {x,y,z} points in python -- ideally something like the Mathematica <a href="http://reference.wolfram.com/mathematica/ref/ListSurfacePlot3D.html" rel="noreferrer"><code>ListSurfacePlot3D</code></a> function. Thus far I've tried <code>plot_surface</code> and <code>plot_wireframe</code> on my points to no avail. Only the axes render with <code>plot_surface</code>. <code>plot_wireframe</code> gives a bunch of squigglys, vaguely in the shape of the object, but not the nice sort that is shown in the documentation: <img src="https://i.stack.imgur.com/IEgG5.png" alt="enter image description here"> Compare to the result from <code>ListSurfacePlot3D</code>: <img src="https://i.stack.imgur.com/JJjQP.png" alt="enter image description here"> Here is a minimal working example, using a test.csv file I posted <a href="http://pastebin.com/0B1z2SBv" rel="noreferrer">here</a>: <pre><code>import csv from matplotlib import pyplot import pylab from mpl_toolkits.mplot3d import Axes3D hFile = open("test.csv", 'r') datfile = csv.reader(hFile) dat = [] for row in datfile: dat.append(map(float,row)) temp = zip(*(dat)) fig = pylab.figure(figsize=pyplot.figaspect(.96)) ax = Axes3D(fig) </code></pre> Then, either <pre><code>ax.plot_surface(temp[0], temp[1], temp[2]) pyplot.show() </code></pre> or <pre><code>ax.plot_wireframe(temp[0], temp[1], temp[2]) pyplot.show() </code></pre> This is how it renders using <code>plot_surface</code>: <img src="https://i.stack.imgur.com/cULvz.png" alt="enter image description here"> and using <code>plot_wireframe</code>: <img src="https://i.stack.imgur.com/9zQhf.png" alt="enter image description here"> and using <code>ListSurfacePlot3D</code>: <img src="https://i.stack.imgur.com/NPXHe.png" alt="enter image description here">
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<python><3d><matplotlib>
Title
Plot a 3D surface from {x,y,z}-scatter data in python
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