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    <p>2 most important issues with you code:</p> <ul> <li>You SHALL check number of arguments BEFORE arguments check.</li> <li>Strings are compared using standard library functions like <code>strcmp()</code> or even better <code>strncmp()</code> if you know maximum length.</li> </ul> <p>Here is the <strong>C code</strong> that works. Hope this help.</p> <pre><code>#include &lt;stdio.h&gt; #include &lt;string.h&gt; int main (int argc, char* argv[]) { if ((argc &gt; 1) &amp;&amp; ((strcmp(argv[1], "a") == 0))) { printf("hello world, argc: %d\n", argc); } else if ((argc &gt; 1) &amp;&amp; (strcmp(argv[1], "2") == 0)) { printf("hello everyone, argc: %d\n", argc); } for (int i = 0; i &lt; argc; i++) printf("%s\n", argv[i]); return 0; } </code></pre> <p>Some details aout string comparison. If you use <code>==</code> operator here (if you have not overloaded it) you just compare object addresses (look carefully, you have <code>char *</code> in both cases). Obviously your string literal and argument buffer have different addresses. You need to compare contents. Actually in C++ you can construct <code>std::string</code> and use comparison operator.</p> <p>So another, <strong>more C++ solution</strong> that works based on <code>==</code> operator:</p> <pre><code>#include &lt;stdio.h&gt; #include &lt;string&gt; int main (int argc, char* argv[]) { if ((argc &gt; 1) &amp;&amp; (std::string(argv[1]) == "a")) { printf("hello world, argc: %d\n", argc); } else if ((argc &gt; 1) &amp;&amp; (std::string(argv[1]) == "2")) { printf("hello everyone, argc: %d\n", argc); } for (int i = 0; i &lt; argc; i++) printf("%s\n", argv[i]); return 0; } </code></pre>
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    1. POWhy does not argv work?
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    1. USRoman Nikitchenko
    1. USRoman Nikitchenko
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      1. VTUpMod
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    1. CO+1 - catched me by 18 seconds :)
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      1. USAndreas Fester
    2. CO@Andreas You still got the chance. It's tagged C++ not C ^^.
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      1. USa3f
    3. CO@a3f Done - see above :D
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      1. USAndreas Fester
 

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