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POWhat happens when more than one thread tries to update form controls using Invoke at the same time in Winforms?
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2013-06-27T05:32:35.957
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2013-06-27T08:28:38.837
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<p>What happens when more than one thread tries to call a form method using Invoke which updates form controls at the same time in Winforms? </p> <pre><code> static thCount = 0; private void button1_Click(object sender, EventArgs e) { System.Threading.Thread t1 = new System.Threading.Thread(start); System.Threading.Thread t2 = new System.Threading.Thread(start); t1.Start(); t2.Start(); } private void start() { System.Threading.Thread.Sleep(300); Invoke(new MethodInvoker(guiUpdate)); } private void guiUpdate() { this.label1.Text = "Updated.." + (thCount++); this.label1.Update(); } private void Form1_Load(object sender, EventArgs e) { this.label1.Text = System.Threading.Thread.CurrentThread.Name; } </code></pre>
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<c#><.net><multithreading><winforms>
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What happens when more than one thread tries to update form controls using Invoke at the same time in Winforms?
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1. COThe best answer should be "the program crashes".
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  POWhat happens when more than one thread tries to update form controls using Invoke at the same time in Winforms?
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  USAlvin Wong
2. COWhy would it crash? I'm not disputing that it may, 'cos I haven't tried it, but would the Invokes not simply be serialized? 'Invoke' is, essentially, SendMessage() API?
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  POWhat happens when more than one thread tries to update form controls using Invoke at the same time in Winforms?
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  USMartin James

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