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POOctal to binary conversion confusion
 

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  1. POOctal to binary conversion confusion
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    <p>I have a code in C++ which convert 2 digits octal number to binary number. For testing validity of the code I used several online conversion site like </p> <p><a href="http://www.translatorscafe.com/cafe/units-converter/numbers/calculator/octal-to-binary/" rel="nofollow">this</a> and <a href="http://ncalculators.com/digital-computation/binary-octal-converter.htm" rel="nofollow">this</a></p> <p>When I enter 58 or 59 in as an octal value it says invalid octal values but when I enter 58 in my code it gives binary number as - 101000. Again for testing I enter 101000 as binary number in above website's calculator then they gives me result 50 as octal value.</p> <p>I need some explanation why this is so.</p> <p>Here is the C++ code -</p> <pre><code>#include &lt;iostream.h&gt; #include &lt;conio.h&gt; void octobin(int); void main() { clrscr(); int a; cout &lt;&lt; "Enter a 2-digit octal number : "; cin&gt;&gt;a; octobin(a); getch(); } void octobin(int oct) { long bnum=0; int A[6]; //Each octal digit is converted into 3 bits, 2 octal digits = 6 bits. int a1,a2,quo,rem; a2=oct/10; a1=oct-a2*10; for(int x=0;x&lt;6;x++) { A[x]=0; } //Storing the remainders of the one's octal digit in the array. for (x=0;x&lt;3;x++) { quo=a1/2; rem=a1%2; A[x]=rem; a1=quo; } //Storing the remainders of the ten's octal digit in the array. for(x=3;x&lt;6;x++) { quo=a2/2; rem=a2%2; A[x]=rem; a2=quo; } //Obtaining the binary number from the remainders. for(x=x-1;x&gt;=0;x--) { bnum*=10; bnum+=A[x]; } cout &lt;&lt; "The binary number for the octal number " &lt;&lt; oct &lt;&lt; " is " &lt;&lt; bnum &lt;&lt; "." &lt;&lt; endl; } </code></pre>
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    1. CO`void main` is not a valid signature for `main`. Use `int main`.
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    2. CO`clrscr` is not a standard C or C++ function. Why do you need to clear the screen each time (it will erase the previous data that may be useful in solving problems)?
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