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PORetrieving database column using JSON
 

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  1. PORetrieving database column using JSON
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    <p>I have a database consist of 4 columns (id-symbol-name-contractnumber). All 4 columns with their data are being displayed on the user interface using JSON.</p> <p>There is a function which is responisble to add new column to the database e.g (countrycode). </p> <p>The coulmn is added successfully to the database BUT not able to show the new added coulmn in the user interface.</p> <p>Below is my code that is displaying the columns. </p> <p>Can you help me?</p> <p>table.php</p> <pre><code> &lt;!DOCTYPE html&gt; &lt;html lang="en"&gt; &lt;head&gt; &lt;link rel="stylesheet" href="../../jqwidgets/styles/jqx.base.css" type="text/css" /&gt; &lt;script type="text/javascript" src="../../scripts/jquery-1.8.3.min.js"&gt;&lt;/script&gt; &lt;script type="text/javascript" src="../../jqwidgets/jqxcore.js"&gt;&lt;/script&gt; &lt;script type="text/javascript" src="../../jqwidgets/jqxbuttons.js"&gt;&lt;/script&gt; &lt;script type="text/javascript" src="../../jqwidgets/jqxscrollbar.js"&gt;&lt;/script&gt; &lt;script type="text/javascript" src="../../jqwidgets/jqxmenu.js"&gt;&lt;/script&gt; &lt;script type="text/javascript" src="../../jqwidgets/jqxgrid.js"&gt;&lt;/script&gt; &lt;script type="text/javascript" src="../../jqwidgets/jqxgrid.selection.js"&gt;&lt;/script&gt; &lt;script type="text/javascript" src="../../jqwidgets/jqxgrid.filter.js"&gt;&lt;/script&gt; &lt;script type="text/javascript" src="../../jqwidgets/jqxdata.js"&gt;&lt;/script&gt; &lt;script type="text/javascript" src="../../jqwidgets/jqxlistbox.js"&gt;&lt;/script&gt; &lt;script type="text/javascript" src="../../jqwidgets/jqxdropdownlist.js"&gt;&lt;/script&gt; &lt;script type="text/javascript" src="../../scripts/gettheme.js"&gt;&lt;/script&gt; &lt;script type="text/javascript"&gt; $(document).ready(function () { // prepare the data var theme = getDemoTheme(); var source = { datatype: "json", datafields: [ { name: 'id' }, { name: 'symbol' }, { name: 'name' }, { name: 'contractnumber' } ], url: 'data.php', filter: function() { // update the grid and send a request to the server. $("#jqxgrid").jqxGrid('updatebounddata', 'filter'); }, cache: false }; var dataAdapter = new $.jqx.dataAdapter(source); // initialize jqxGrid $("#jqxgrid").jqxGrid( { source: dataAdapter, width: 670, theme: theme, showfilterrow: true, filterable: true, columns: [ { text: 'id', datafield: 'id', width: 200 }, { text: 'symbol', datafield: 'symbol', width: 200 }, { text: 'name', datafield: 'name', width: 100 }, { text: 'contractnumber', filtertype: 'list', datafield: 'contractnumber' } ] }); }); &lt;/script&gt; &lt;/head&gt; &lt;body class='default'&gt; &lt;div id="jqxgrid"&gt;&lt;/div&gt; &lt;/div&gt; &lt;/body&gt; &lt;/html&gt; </code></pre> <p>data.php</p> <pre><code> &lt;?php #Include the db.php file include('db.php'); #Connect to the database //connection String $connect = mysql_connect($mysql_hostname, $mysql_user, $mysql_password) or die('Could not connect: ' . mysql_error()); //Select The database $bool = mysql_select_db($mysql_database, $connect); if ($bool === False){ print "can't find $database"; } $query = "SELECT * FROM pricelist"; $result = mysql_query($query) or die("SQL Error 1: " . mysql_error()); $orders = array(); // get data and store in a json array while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) { $orders[] = array( 'id' =&gt; $row['id'], 'symbol' =&gt; $row['symbol'], 'name' =&gt; $row['name'], 'contractnumber' =&gt; $row['contractnumber'] ); } echo json_encode($orders); ?&gt; </code></pre>
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