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POPython regex chokes on \n
 

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    <p>I wish to use a regex in Python that reads text, finds all instances in which &lt; emotion > markup exists within the same sentence as &lt; location > markup, then allows those sentences to be print to a unique line of an output file:</p> <pre><code>import re out = open('out.txt', 'w') readfile = "&lt;location&gt; Oklahoma &lt;/location&gt; where the wind comes &lt;emotion&gt; sweeping &lt;/emotion&gt; down &lt;location&gt; the plain &lt;/location&gt;. And the waving wheat. It can sure smell &lt;emotion&gt; sweet &lt;/emotion&gt;." for match in re.findall(r'(?:(?&lt;=\.)\s+|^)((?=(?:(?!\.(?:\s|$)).)*?\bemotion&gt;(?=\s|\.|$))(?=(?:(?!\.(?:\s|$)).)*?\blocation&gt;(?=\s|\.|$)).*?\.(?=\s|$))', readfile, flags=re.I): line = ''.join(str(x) for x in match) out.write(line + '\n') out.close() </code></pre> <p>The trouble is that if I read in a file that contains line breaks, the regex fails:</p> <pre><code>import re out = open('out.txt', 'w') readfile = "&lt;location&gt; Oklahoma &lt;/location&gt; where the wind \n comes &lt;emotion&gt; sweeping &lt;/emotion&gt; down &lt;location&gt; the plain &lt;/location&gt;. And the waving wheat. It can sure smell &lt;emotion&gt; sweet &lt;/emotion&gt;." for match in re.findall(r'(?:(?&lt;=\.)\s+|^)((?=(?:(?!\.(?:\s|$)).)*?\bemotion&gt;(?=\s|\.|$))(?=(?:(?!\.(?:\s|$)).)*?\blocation&gt;(?=\s|\.|$)).*?\.(?=\s|$))', readfile, flags=re.I): line = ''.join(str(x) for x in match) out.write(line + '\n') out.close() </code></pre> <p>Is there any way to modify this regular expression so that it won't choke when it hits \n? I would be most grateful for any advice others can lend on this question.</p>
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    1. COEither read the file as lines, or strip out the newline character before applying the regex.
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