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    <p>Partial function helps you to pre fill the function arguments that is always needed for the function execution. This helps is reducing the overheads in many ways. </p> <p>The example above helps in filling undefined arguments later.</p> <p>The <em>arg</em> is a private variable to keep track of the undefined arguments and fill the undefined arguments in sequence. </p> <pre><code>args[i] = arguments[arg++]; </code></pre> <p>The above line filling the undefined arguments those were left undefined when using partial.</p> <p>Example:-</p> <p>function a(b,c){ console.log(b,c); }</p> <p>//pre filling the second argument with numeric value 1. But first argument is still undefined. This will return a new function.</p> <pre><code>var g = a.partial(undefined, 1); </code></pre> <p>//Now when you actually invoke the function and pass it the parameters this will fill the arguments left undefined previously i.e. "b" . In this case the <em>var arg</em> will fill the previous <em>args</em> array position those were undefined i.e. args[0] was undefined. So <em>var arg</em> will read the passed arguments in sequence and fill the previously undefined arguments for you.</p> <pre><code>g("Hi I was undefined before"); </code></pre> <p>If don't want to <em>args</em> gets permanently change then update the <em>partial</em> implementation as below.</p> <pre><code>Function.prototype.partial = function() { var fn = this, args = Array.prototype.slice.call(arguments); return function() { var arg = 0, g;//g will hold the clone of args g = args.slice(0);//clone the args array and use that instead of original args. for (var i = 0; i &lt; g.length &amp;&amp; arg &lt; arguments.length; i++) { if (g[i] === undefined) { g[i] = arguments[arg++]; } } return fn.apply(this, g); }; }; function fn(a, b){ } var fn = f.partial(undefined, 3), x = fn(2), y= fn(4);//Now this will work </code></pre>
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    1. POUnderstanding Jon Resig's implementation of partial application
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    1. CODoes the array `args`get changed permanently once you call the curried function? Does `var fn = f.partial(undefined, 3), x = fn(2), y= fn(4);` work?
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      1. USEric Jablow
    2. CO@EricJablow yes, the args get changed permanently. "Does var fn = f.partial(undefined, 3), x = fn(2), y= fn(4); work?". This will not work because the args is permanently changed. If you don't want it to change it permanently then you need to create a clone of args array and use that clone instead of args. I have updated the answer in which the args will not get changed permanently and you can call it many a time.
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