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    <p>Did you try SAX XML Parser for your work. If not then try it once ...</p> <p>your XML file is:</p> <pre><code>&lt;?xml version="1.0"?&gt; &lt;company&gt; &lt;staff&gt; &lt;firstname&gt;yong&lt;/firstname&gt; &lt;lastname&gt;mook kim&lt;/lastname&gt; &lt;nickname&gt;mkyong&lt;/nickname&gt; &lt;salary&gt;100000&lt;/salary&gt; &lt;/staff&gt; &lt;staff&gt; &lt;firstname&gt;low&lt;/firstname&gt; &lt;lastname&gt;yin fong&lt;/lastname&gt; &lt;nickname&gt;fong fong&lt;/nickname&gt; &lt;salary&gt;200000&lt;/salary&gt; &lt;/staff&gt; &lt;/company&gt; </code></pre> <p>JAVA CODE for XML parser</p> <pre><code>import javax.xml.parsers.SAXParser; import javax.xml.parsers.SAXParserFactory; import org.xml.sax.Attributes; import org.xml.sax.SAXException; import org.xml.sax.helpers.DefaultHandler; public class ReadXMLFile { public static void main(String argv[]) { try { SAXParserFactory factory = SAXParserFactory.newInstance(); SAXParser saxParser = factory.newSAXParser(); DefaultHandler handler = new DefaultHandler() { boolean bfname = false; boolean blname = false; boolean bnname = false; boolean bsalary = false; public void startElement(String uri, String localName,String qName, Attributes attributes) throws SAXException { System.out.println("Start Element :" + qName); if (qName.equalsIgnoreCase("FIRSTNAME")) { bfname = true; } if (qName.equalsIgnoreCase("LASTNAME")) { blname = true; } if (qName.equalsIgnoreCase("NICKNAME")) { bnname = true; } if (qName.equalsIgnoreCase("SALARY")) { bsalary = true; } } public void endElement(String uri, String localName, String qName) throws SAXException { System.out.println("End Element :" + qName); } public void characters(char ch[], int start, int length) throws SAXException { if (bfname) { System.out.println("First Name : " + new String(ch, start, length)); bfname = false; } if (blname) { System.out.println("Last Name : " + new String(ch, start, length)); blname = false; } if (bnname) { System.out.println("Nick Name : " + new String(ch, start, length)); bnname = false; } if (bsalary) { System.out.println("Salary : " + new String(ch, start, length)); bsalary = false; } } }; saxParser.parse("c:\\file.xml", handler); } catch (Exception e) { e.printStackTrace(); } } } </code></pre> <p>your out put is :</p> <pre><code>Start Element :company Start Element :staff Start Element :firstname First Name : yong End Element :firstname Start Element :lastname Last Name : mook kim End Element :lastname Start Element :nickname Nick Name : mkyong End Element :nickname Start Element :salary Salary : 100000 End Element :salary End Element :staff Start Element :staff Start Element :firstname First Name : low End Element :firstname Start Element :lastname Last Name : yin fong End Element :lastname Start Element :nickname Nick Name : fong fong End Element :nickname Start Element :salary Salary : 200000 End Element :salary End Element :staff End Element :company </code></pre>
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    1. POHow to get value of a particular xml tag having same names and no attribute while parsing xml in sax parser
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    1. USuser1690439
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    1. COHI, I tried with SAX parser only as thats the best if you are creating app on android. I have tried the above example also. I know it works but the thing is i only want one value as String and not all. Like to explain from the above example, i would like only (yin fong) to be returned but not mook kim or any other names in the tags. I tried counter also but not sure how to implement. i tried putting if(counter<10){ confName = qName; } in start element method but still it gives all the emails
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      1. USMayank Kalbhor
    2. COFor that you also implement regex or pattern like if you want to add some specific name with the tag
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    3. COThanks guys... Counter variable worked perfectly.
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      1. USMayank Kalbhor
 

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