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POHow does changing the position of the BaseStream of a BinaryReader affect the current state of a BinaryWriter that uses the same BaseStream?
 

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  1. POHow does changing the position of the BaseStream of a BinaryReader affect the current state of a BinaryWriter that uses the same BaseStream?
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    <p>I am working on a parser that watches a stream (probably from a <code>NetworkStream</code>). When certain data is seen on the source stream, a new <code>MemoryStream</code> is created and the relevant data from the source is written to it.</p> <p>Then I pass the <code>MemoryStream</code> for parsing to another class method that parses the <code>MemoryStream</code> as a <code>Stream</code>. In this method a <code>BinaryReader</code> is created. When it goes to read the data there is none because the <code>BinaryReader</code> is actually at the end of the data.</p> <p>The BinaryReader does not have a <code>Position</code> property or <code>Seek</code> method, so the underlining <code>BaseStream</code> position needs to be changed. Once the position is changed the stream can be parsed.</p> <p>In this case we are not adding additional data so there is no problem. But the thought occurs to me that if a similar situation arrives and additional data is going to be written to the this might not work because the position value was changed behind its back.</p> <p>I’m a bit fuzzy on the implications here.</p> <p>Do the writer and reader work with copies of the <code>BaseStream</code> and its position or the original object allowing for corruption?</p> <p>Does this mean that I need to create the reader at the same time I create the writer so that both start at the same spot then pass then reader to the method instead of the <code>BaseStream</code>? I think this might be a better practice.</p> <p>Does the BinaryReader and Writer maintain their own position information? I'm thing not because the property isn't there. If not can you use them concurrently in the same thread?</p> <p><strong>Update #1:</strong> Based on an answer and comments that have since been withdrawn I think I need to make my confusion a little clearer. There is a <code>BaseStream</code> property in both <code>BinaryWriter</code> and <code>BinaryReader</code>. I thought it pointed to the stream object that was used to create the writer and reader. I’m starting to think it is just a worker object that is unique to both.</p> <p>I don’t want to assume to much about the stream objects so that I remain open to multiple types of streams as a source.</p> <p><strong>Update #2:</strong> Now after running some test code I see that they are connected. When data is written it affects the position of the reader. I would have thought to be useful the reader would remain unaffected so that it could pick up where it left off, reading the next part of the stream. I envisioned something like this:</p> <ul> <li>A data event occurs. The event causes data to be written by the writer.</li> <li>At some point the reader works on some of the data in the stream.</li> <li>Another event occurs causing more data to be written.</li> <li>It is appended to the data that the reader already is working on.</li> <li>The reader finishes its work including new data.</li> </ul> <p>But based on the way the position works between the reader and writer this is not the way the stream is to be used,.</p> <p>Maybe my conception problem is because my BaseStream is a MemoryStream and the rules are different than it would be with a NetworkStream. I was trying to keep the implementation details of the stream's source out of the reading class.</p> <p>I guess at this point I have the answer to the question. Now I need to find information on using streams to do the type of thing that I have in my head.</p>
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    1. USRich Shealer
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