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POWhy speed of variable length pipeline is determined by the slowest stage + whats the total execution time of program?
 

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  1. POWhy speed of variable length pipeline is determined by the slowest stage + whats the total execution time of program?
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    <p>I am new to pipelining and I need some help regarding the fact that</p> <blockquote> <p><strong>The speed of the pipelining is determined by the speed of the slowest stage</strong></p> </blockquote> <p>Not only this, if I am given a 5 stage pipeline with duration of them 5 ns,10 ns, 8 ns, 7 ns,7 ns respectively , it is said that each instruction would take 10 ns time. Can I get a clear explanation for this?</p> <p><strong>(edited</strong>) Also let my program has 3 instructions I1,I2,I3 and I take 1 clk cycle duration = 1ns such that the above stages take - 5, 10, 8 , 7 , 7 clock cycles respectively. Now according to theory a snapshot of the pipeline would be - </p> <p><img src="https://i.stack.imgur.com/dmACt.png" alt="Simple Pipeline snapshot"></p> <p>But that gives me a total time to be -no of clk cycles*clk cycle duration = 62 * 1 = 62 ns But according to theory total time should be - (slowest stage) * no. of instructions = 10 * 3 = 30 ns Though I have an idea why slowest stage is important (each pipeline stage needs to wait hence 1 instruction is produced after every 10 clk cycle- but the result is inconsistent when i calculate it using clk cycles.Why this inconsistency? What am I missing?? <strong>(edited)</strong></p>
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