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POFor loop without the second condition, i.e. the boolean check?
 

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  1. POFor loop without the second condition, i.e. the boolean check?
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    <p>I have to write a function that calculates the floor of log base 16 of an unsigned int passed in. There are restrictions as to what operators and what constants we are allowed to use, and we can only use specifically <code>for</code> loops. </p> <p>For clarity, we cannot use any conditional statements(if, else, switch ... ). The function prototype is: </p> <pre><code>int floor_log16(unsigned int x); </code></pre> <p>Allowed operators: <code>++</code> <code>--</code> <code>=</code> <code>&amp;</code> <code>|</code> <code>~</code> <code>^</code> <code>&lt;&lt;</code> <code>!</code> <code>&gt;&gt;</code></p> <p>Allowed constants: <code>1</code> <code>2</code> <code>3</code> <code>4</code> <code>8</code> <code>16</code></p> <p>I wrote a version of the program as follows:</p> <pre><code>int floor_log16(unsigned int x) { int index=1; int count=(1!=1); count--; for(; index&lt;=x; index&lt;&lt;=4) { count++; } return count; } </code></pre> <p>which seems to work as desired. However, I realized that based on the later functions and description of the needed functionality we have to write, I noticed that under "allowed operators" sometimes <code>&gt;</code> and <code>&lt;</code> were listed. </p> <p>I deduce this implies that since for the <code>floor_log16</code> function listed above, we weren't explicitly told to use <code>&gt;</code> or <code>&lt;</code>, I can only assume that the solution posted above will not be accepted. </p> <p>This leaves me rather confused because I don't understand how you can possibly have a for loop without a boolean check? </p> <p>Isn't the whole idea of a loop to iterate while a condition is met? </p>
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    1. USKen Kin
    1. USArthur Collé
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      1. USSoufiane Hassou
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    1. COFor interest sake, you can make an if-statement using a for-loop, so the if-statement restriction is somewhat trivial (similarly for the `else`) - `if (condition) statement;` = `for(;condition;) {statement; break;}`, but I don't suppose you're meant to do that.
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      1. USDukeling
    2. COMaybe something like `for(;x;x>>4)` ? which will stop when `x == 0`
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      1. USSoufiane Hassou
    3. CO"I don't understand how you can possibly have a for loop without a boolean check?" -- The for loop itself does a boolean check ... it either continues or ends depending on the value of an expression. "Isn't the whole idea of a loop to iterate while a condition is met?" -- No, it's to iterate while the expression is non-zero. This would be clear to you if you were to actually read the documentation rather than philosophizing on "the whole idea" of things. Consider that students with the right intellectual skills will get better grades and get the jobs.
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      1. USJim Balter
 

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