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    <p>As stated in the comments Eric Lippert has a blog post named <a href="http://ericlippert.com/2010/06/28/computing-a-cartesian-product-with-linq/" rel="nofollow">Computing a Cartesian Product with LINQ</a> that explains how to solve your problem. You need an extension method to compute the cartesian product:</p> <pre><code>public static IEnumerable&lt;IEnumerable&lt;T&gt;&gt; CartesianProduct&lt;T&gt;(this IEnumerable&lt;IEnumerable&lt;T&gt;&gt; sequences) { IEnumerable&lt;IEnumerable&lt;T&gt;&gt; result = new [] { Enumerable.Empty&lt;T&gt;() }; foreach (var sequence in sequences) { var localSequence = sequence; result = result.SelectMany( _ =&gt; localSequence, (seq, item) =&gt; seq.Concat(new[] { item }) ); } return result; } </code></pre> <p>Then you need a sequence of sequences to perform the product over. In your case you have both strings and integers in your sequences so the common base type <code>T</code> has to be <code>Object</code>.</p> <pre><code>var sequences = new[] { new Object[] { "black", "white", "red" }, new Object[] { 30, 32, 34, 36, 38 }, new Object[] { 28, 30, 32, 34 } }; </code></pre> <p>To compute the Cartesian product you simply invoke the extension method:</p> <pre><code>var result = sequences.CartesianProduct(); </code></pre> <p>When you enumerate the result it is computed on the fly (lazily). If you prefer to create a list of lists you need to call <code>ToList()</code> after <code>Concat</code> and also before returning <code>result</code> from the extension method.</p>
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