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POHow to decrypt pbkdf2 encrypted text without knowing the IV
 

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  1. POHow to decrypt pbkdf2 encrypted text without knowing the IV
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    <p>I am trying to decrypt an encrypted text. I have the salt value, iteration count and key length. But i don't have the initialization vector (IV) value, how can i go about and decrypt this. I also have secret key.</p> <p>For time being I am using some random IV value whose size is 16 bytes. But still i am not able to decrypt the value properly. Can anyone please help as i am stuck with this for a long time?</p> <hr> <p>Below are the values which were given to me.</p> <pre><code>salt= EW0h0yUcDX72WU9UiKiCwDpXsJg=, Iteration=128,Keylenght=16. MasterKeyName="Passphrase1", MACMethod algo = hmac-sha1, MACKey="jq/NdikC7AZf0Z+HEL5NrCICV8XW+ttzl/8687hVGHceoyJAaFws+111plQH 6Mlg" encrypted kae = "pM7VB/KomPjq2cKaxPr5cKT1tUZN5tGMI+u1XKJTG1la+ThraPpLKlL2plKk6vQE" and valuemac="lbu+9OcLArnj6mS7KYOKDa4zRU0=". Secret key = "xxxxxxxxxxx". </code></pre> <hr> <p>Below is the code which I am using to decrypt.</p> <pre><code>SecretKeyFactory factory = SecretKeyFactory.getInstance("PBKDF2WithHmacSHA1"); KeySpec spec = new PBEKeySpec(secretkey.toCharArray(), salt, iterationCount, keyStrength); SecretKey tmp = factory.generateSecret(spec); key = new SecretKeySpec(tmp.getEncoded(), "AES"); dcipher = Cipher.getInstance("AES/CBC/PKCS5Padding"); AlgorithmParameters params = dcipher.getParameters(); iv = "0000000000000000".getBytes(); System.out.println("IV " + new sun.misc.BASE64Encoder().encodeBuffer(iv)); dcipher.init(Cipher.DECRYPT_MODE, key, new IvParameterSpec(iv)); byte[] decryptedData = new sun.misc.BASE64Decoder().decodeBuffer(base64EncryptedData); byte[] utf8 = dcipher.doFinal(decryptedData); </code></pre>
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      1. VTUpMod
    1. COPBKDFv2 is a **hash**. It is (hopefully) mathematically impossible to decrypt.
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      1. USSLaks
    2. COWhen you decrypt, do you get 16 bytes of rubbish followed by the correctly decrypted message? If so, then the first sixteen bytes of the cyphertext are the IV.
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      1. USrossum
    3. COPlease not that being able to decrypt without an exception does not mean you have found the key; any ciphertext with the correct block size decrypts for a block cipher that does not use an authenticated encryption mode. It just decrypts to garbage.
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      1. USMaarten Bodewes
 

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