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    <p>Jhonnatan, I'm glad you got your code working. So this isn't really an "answer" to your original question. But you also asked for tips on the coding and how to improve it. That's great that you're looking for ways to improve your code!</p> <p>Here's one suggestion for you, a simpler way to write the <code>checkUser()</code> function. This is just a direct conversion of your function that should work with the same data format.</p> <pre><code>function checkUser() { console.log( "clicked" ); var user = $(this).html(); $.getJSON( "js/options.json", function( json ) { $.each( json.chat.OnlineContacts, function( i, contact ) { if( user == contact.name ) { displayChatWindow( contact.name, contact.status, contact.avatar ); console.log( contact.avatar ); } }); }); } </code></pre> <p>Note how the use of the <code>contact</code> object makes it unnecessary to create all those <code>jsonUserXxxx</code> variables, because code like <code>contact.avatar</code> is just as simple and clear as <code>jsonUserAvatar</code>.</p> <p>I also highly recommend <a href="https://stackoverflow.com/a/16972266/1202830">@DaveRomero's excellent answer</a> for a more strategic look at the question of how best to structure your JSON data.</p> <p>More related reading: <a href="https://stackoverflow.com/a/16971541/1202830">this discussion of JSON restructuring</a> that I posted in response to <a href="https://stackoverflow.com/questions/16970265/find-json-nested-nodes-using-multiple-string-values">this question</a> earlier today.</p>
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    1. USMichael Geary
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    1. COHello Michael, thank you for taking the time to answer and also add all that material and examples :). when you refer to an object I got a question. Like "contact.avatar" how can i convert the json I get by $.getJSON in to an object like contact={} as you said. I dont really get it on how to convert all the data in the json to an object, or is the $,each doing it for me? I am sorry if the question is not 100% understandable, english is not my main lenguage so I am doing a great effor lol.
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      1. USJhonnatan Gonzalez Rodriguez
    2. CO@JhonnatanGonzalezRodriguez - Yes, `$.each` provides that `contact` object to its callback function. In your original code, `json.chat.OnlineContacts` is already an array of `contact` objects, right? That's why you could use `json.chat.OnlineContacts[i]` to get to one of those objects, or `json.chat.OnlineContacts[i].avatar` to get to one avatar. `$.each` just loops through the array for you, and calls the nested callback function for each array element, passing it the array index and array value - the `contact` object - as parameters. (And BTW your English is very good!)
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