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    <p>I don't really get where you're heading with those two lists structure. It's unclear, and I don't think you can get a proper algorithm out of that. </p> <p>You say: "For a given text if any of the words in position_list occurs, it must be replaced with specific words in position", that means that '<em>front</em>' has to be replaced by '<em>down</em>', '<em>frnt</em>' by '<em>right</em>' and '<em>rhs</em>' has no replacement. That makes no sense!</p> <p>So I'm guessing, from the rest of your question, that you want the words that follows '<em>front</em>' to be replaced by '<em>front</em>', and the words that follows '<em>back</em>' to be replaced by '<em>back</em>'. But then, there's no information to help an algorithm know what words are the replacements, and what words are to be replaced.</p> <p>So the only solution would be to change your structures in a more pythonic way to make an easy and elegant algorithm out of it. Then, you may want to try with a structure like this:</p> <pre><code>position = ['front', 'back'] position_list = [('frnt', 'ft'), ('bck')] </code></pre> <p>and then the algorithm would look like:</p> <pre><code>replaces = zip(position, position_list) for new_word, old_words in replaces: for old_word in old_words: str = str.replace(old_word, new_word) </code></pre> <p>You can also use a dictionary:</p> <pre><code>positions = {'front': ['frnt', 'ft'], 'back': ['bck']} for new_word, old_words in positions.iteritems(): for old_word in old_words: str = str.replace(old_word, new_word) </code></pre> <p>In other words, try avoiding creating structures that would lead in the end making an algorithm dealing with indexes of the list...</p>
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    1. POReplacing words in a list occuring in a text with words in another list
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    1. COis it possible that for string "please drive 2 km ft after next cross" your solution will not work?
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    2. COnot sure if that's what you're spotting, but I just corrected the solution, I carelessly interverted the indexes in the outer for while writing it ;-)
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    3. CO"please drive 2 km **ft** a **ft** er next cross"
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