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POHow to pass the Now() Function from one page to another in php
 

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    <p>I am displaying the <code>timestamp=now()</code> from one page to another. How can I pass this function? As on the second page I want to retrieve the table on the basis of <code>timestamp=now()</code>. I have done this but it's not working. Kindly help me in this.</p> <p>Coding</p> <pre><code>&lt;script type="text/javascript" charset="utf-8"&gt; function showCustomer(n) { var xmlhttp; if (window.XMLHttpRequest) {// code for IE7+, Firefox, Chrome, Opera, Safari xmlhttp=new XMLHttpRequest(); } else {// code for IE6, IE5 xmlhttp=new ActiveXObject("Microsoft.XMLHTTP"); } xmlhttp.onreadystatechange=function() { if (xmlhttp.readyState==4 &amp;&amp; xmlhttp.status==200) { document.getElementById("display").innerHTML=xmlhttp.responseText; } } alert(n); xmlhttp.open("POST","display.php?id="+ n,true); xmlhttp.send(); } &lt;/script&gt; &lt;/head&gt; &lt;body&gt; &lt;form&gt; &lt;?php $s= 'now()'; echo $s; ?&gt; &lt;input type="button" value="h" name="s" onclick="showCustomer(&lt;?php $s ?&gt;)"&gt; &lt;div id='display' &gt; &lt;?php echo "111"; ?&gt; &lt;/div&gt; </code></pre> <p>I retrieve the data from the database through this coding:</p> <pre><code>&lt;?php include('config.php'); $sa="select * from table1 where timestamp=now()"; $result=mysql_query($sa) or die(mysql_error()); echo "&lt;table border='1'&gt; &lt;tr&gt; &lt;/tr&gt;";?&gt; &lt;?php while($row = mysql_fetch_array($result)) { $row['c1']; $row['c2']; $row['c3']; $row['c4']; } </code></pre> <p>I must call this table on button click on next page by also considering the Now() function. Kindly help me.</p>
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    1. COPlease pass the now() as a GET parameter the same way you pass the ID.
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    2. COstring must be quoted in js
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    3. COFYI: `mysql_` queries are deprecated and open to SQL injections. Use `mysqli` instead.
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