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    <p>You are doing bitwise operations here: <code>if(!characterAtEnd.equals(String.valueOf(0|1|2|3|4|5|6|7|8|9)))</code></p> <p>Check out the difference between <code>|</code> and <code>||</code></p> <p>This bit of code should accomplish your task using regular expressions:</p> <pre><code>String code = "45m4av7"; if (!code.matches("^.+?\\d$")){ System.out.println("INVALID CRC CODE"); } </code></pre> <p>Also, for reference, this method sometimes comes in handy in similar situations:</p> <pre><code>/* returns true if someString actually ends with the specified suffix */ someString.endsWith(suffix); </code></pre> <p>As <code>.endswith(suffix)</code> does not take regular expressions, if you wanted to go through all possible lower-case alphabet values, you'd need to do something like this:</p> <pre><code>/* ASCII approach */ String s = "hello"; boolean endsInLetter = false; for (int i = 97; i &lt;= 122; i++) { if (s.endsWith(String.valueOf(Character.toChars(i)))) { endsInLetter = true; } } System.out.println(endsInLetter); /* String approach */ String alphabet = "abcdefghijklmnopqrstuvwxyz"; boolean endsInLetter2 = false; for (int i = 0; i &lt; alphabet.length(); i++) { if (s.endsWith(String.valueOf(alphabet.charAt(i)))) { endsInLetter2 = true; } } System.out.println(endsInLetter2); </code></pre> <p>Note that neither of the aforementioned approaches are a good idea - they are clunky and rather inefficient. </p> <p>Going off of the ASCII approach, you could even do something like this:</p> <p>ASCII reference : <a href="http://www.asciitable.com/" rel="nofollow">http://www.asciitable.com/</a></p> <pre><code>int i = (int)code.charAt(code.length() - 1); /* Corresponding ASCII values to digits */ if(i &lt;= 57 &amp;&amp; i &gt;= 48){ System.out.println("Last char is a digit!"); } </code></pre> <p>If you want a one-liner, stick to regular expressions, for example:</p> <pre><code>System.out.println((!code.matches("^.+?\\d$")? "Invalid CRC Code" : "Valid CRC Code")); </code></pre> <p>I hope this helps! </p>
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    1. COHi! Thanks for your response. I tried using the .endsWith method you mentioned, and it seems to have worked well. My only concern is that it seems as though i'd need to re-paste the line of code 26 times for each letter of the alphabet. Whereas I'd really like be able to say "if code ends with a or b or c or d...etc then print "invalid code". So I could have it all nice in one if statement. is that possible? also, I was wondering if for the .matches method, if it looks at what the items in the parenthesis are individually, or as a whole?
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    2. COUnfortunately endswith(suffix) does not take regular expressions (to my knowledge), and if you wanted to check for every letter of the alphabet, you could use a loop (although it would be clunky). As far as the .matches method is concerned, it looks at the last item to make sure that it is a decimal. I've modified my posting to help you out =) Good luck!
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