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POComparing String Integers Issue
 

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  1. POComparing String Integers Issue
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    <p>I have a scanner that reads a 7 character alphanumeric code (inputted by the user). the String variable is called "code". </p> <p>The last character of the code (7th character, 6th index) MUST BE NUMERIC, while the rest may be either numeric or alphabetical. </p> <p>So, I sought ought to make a catch, which would stop the rest of the method from executing if the last character in the code was anything but a number (from 0 - 9).</p> <p>However, my code does not work as expected, seeing as even if my code ends in an integer between 0 and 9, the if statement will be met, and print out "last character in code is non-numerical).</p> <p>example code: 45m4av7</p> <p>CharacterAtEnd prints out as the string character 7, as it should. however my program still tells me my code ends non-numerically. I'm aware that my number values are string characters, but it shouldnt matter, should it? also I apparently cannot compare actual integer values with an "|", which is mainly why im using String.valueOf, and taking the string characters of 0-9.</p> <pre><code>String characterAtEnd = String.valueOf(code.charAt(code.length()-1)); System.out.println(characterAtEnd); if(!characterAtEnd.equals(String.valueOf(0|1|2|3|4|5|6|7|8|9))){ System.out.println("INVALID CRC CODE: last character in code in non-numerical."); System.exit(0); </code></pre> <p>I cannot for the life of me, figure out why my program is telling me my code (that has a 7 at the end) ends non-numerically. It should skip the if statement and continue on. right?</p>
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    1. USSmashAdams
    1. USSmashAdams
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    1. COtry using regex. [Link](http://www.addedbytes.com/cheat-sheets/regular-expressions-cheat-sheet/)
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    2. COPlease tag your question with the programming language.
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      1. USBarmar
    3. COhttp://stackoverflow.com/questions/1223052/how-do-i-find-out-if-first-character-of-a-string-is-a-number
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      1. POComparing String Integers Issue
      1. USPrashant Kumar
 

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