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POProblems with php date
 

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  1. POProblems with php date
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    <p>I've run into a bit of trouble with the PHP date function (I have almost 0 knowledge when it comes to this).</p> <p>I want to get the next 5 days of the week saved in 3 parameter like variables such as <code>$month</code>, <code>$dayofmonth</code> and <code>$dayofweek</code> and having it displayed June 4 Tuesday, each part of the date to be able to be put inside its coresponding html div elements.</p> <p>I've experimented for the last 2 days with different codes but none worked and 3 hours ago I came to the conclusion that the way I was getting the month, I would have a conflict at the end of the month, because the name changes. So I would have had May 31 Friday, May 1 Saturday, May 2 Sunday etc.</p> <p>What i have for now, i think i've corrected the problem with end of the month.</p> <pre><code>$month = date("F"); $day_1 = date("j"); $day_2 = date("j", strtotime("+1 days")); $day_3 = date("j", strtotime("+2 days")); $day_4 = date("j", strtotime("+3 days")); $day_5 = date("j", strtotime("+4 days")); $wday_1 = date("l"); $wday_2 = date("l", strtotime("+1 weekday")); $wday_3 = date("l", strtotime("+1 weekday")); $wday_4 = date("l", strtotime("+1 weekday")); $wday_5 = date("l", strtotime("+1 weekday")); $next_month = date("F", strtotime("+1 month")); echo $day_1." ".$wday_1." "; if($day_1 == 28 || $day_1 == 29 || $day_1 == 30 || $day_1 == 31 || $day_2 == 28 || $day_2 == 29 || $day_2 == 30 || $day_2 == 31 || $day_3 == 28 || $day_3 == 29 || $day_3 == 30 || $day_3 == 31 || $day_4 == 28 || $day_4 == 29 || $day_4 == 30 || $day_4 == 31 || $day_5 == 28 || $day_5 == 29 || $day_5 == 30 || $day_5 == 31) { $month = $next_month; } echo $month; </code></pre> <p>I have read the documentation about date but i need every part of the date in a different variable that can be easily used in localisation changes and SQL selects.</p>
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    1. COYou need to show us your code. There's a VERY easy way to do what you're describing, if only you'd be more specific about what that is and what you've tried.
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    2. COAt this moment i have no more code, i've started again from scratch, i'll post when i get something done that tends to work somewhat how it should. ~20/30 minutes
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      1. USAlex Irhazi
    3. COHave you tried using `strtotime('+1 days');`, changing 1 to whatever amount you need?
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