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    <p>You can do that but you have to check the path to make sure it doesn't point outside your desired sandbox. <code>open</code> won't do it for you. </p> <p>Look at <a href="http://ruby-doc.org/core-2.0/File.html#method-c-realpath" rel="nofollow"><code>File.realpath</code></a>. It resolves <code>..</code> components in the path leaving you with the real path being requested. That path must exist or <code>realpath</code> will raise an exception, which is your first hint that you can't serve the file. You'll need to rescue <code>Errno::ENOENT</code>:</p> <pre><code>File.realpath('/usr/bin') # =&gt; "/usr/bin" File.realpath('/tmp') # =&gt; "/private/tmp" File.realpath('/foobar') Errno::ENOENT: No such file or directory - /foobar </code></pre> <p>Then you can check using a simple regex to make sure the resulting path is anchored in the area or areas you allow. Here's an example of the code.</p> <pre><code>SHARED_PATH_REGEXP = /\A#{ Regexp.escape(File.realpath('/path/to/shared/content')) }/i def is_shared_path?(requested_path) real_requested_path = File.realpath(requested_path) !!real_requested_path[SHARED_PATH_REGEXP] rescue Errno::ENOENT false end path_received('/etc/passwd') # =&gt; false path_received(SHARED_PATH_REGEXP + '/foo.html') # =&gt; true </code></pre> <p><code>Regexp.escape</code> is useful for preprocessing the file string so the regular expression engine does a literal check:</p> <pre><code>Regexp.escape('/usr/bin') # =&gt; "/usr/bin" Regexp.escape('../../public') # =&gt; "\\.\\./\\.\\./public" </code></pre>
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