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    <p>You can use <a href="http://www.regular-expressions.info/lookaround.html" rel="nofollow">lookaround</a> syntax to match <code>?cid=something</code> preceded by the URL and followed by a <code>'</code></p> <p>This pattern should work:</p> <pre><code>(?&lt;=\Qhttps://www.mydomain.com/shop/bags\E)\?cid=[^']++(?=') </code></pre> <p>If you replace that pattern with your replacement then the entire bit from <code>?cid</code> until <code>'</code> will be replaced.</p> <p>Here is an example in Java (ignore the slightly different syntax):</p> <pre><code>public static void main(String[] args) { final String[] in = { "onclick=\"location.href='https://www.mydomain.com/shop/bags?cid=Black'", "onclick=\"location.href='https://www.mydomain.com/shop/bags?cid=Beige'", "onclick=\"location.href='https://www.mydomain.com/shop/bags?cid=Green'" }; final Pattern pattern = Pattern.compile("(?&lt;=\\Qhttps://www.mydomain.com/shop/bags\\E)\\?cid=[^']++(?=')"); for(final String string : in) { final Matcher m = pattern.matcher(string); final String replaced = m.replaceAll("SOMETHING_ELSE"); System.out.println(replaced); } } </code></pre> <p>Output</p> <pre><code>onclick="location.href='https://www.mydomain.com/shop/bagsSOMETHING_ELSE' onclick="location.href='https://www.mydomain.com/shop/bagsSOMETHING_ELSE' onclick="location.href='https://www.mydomain.com/shop/bagsSOMETHING_ELSE' </code></pre> <p>This assumes, obviously, that your tools supports lookaround.</p> <p>This should certainly work if you just use Perl directly rather than via your magic tool</p> <pre><code>perl -pi -e '/s/(?&lt;=\Qhttps://www.mydomain.com/shop/bags\E)\?cid=[^\']++(?=\')/SOMETHING_ELSE/g' *some_?glob*.pattern </code></pre> <p><strong>EDIT</strong></p> <p>Another idea is to use a capturing group and a backreference, replace</p> <pre><code>(\Qhttps://www.mydomain.com/shop/bags\E)\?cid=[^']++ </code></pre> <p>With</p> <pre><code>$1SOMETHING_ELSE </code></pre> <p>Another test case in Java:</p> <pre><code>public static void main(String[] args) { final String[] in = { "onclick=\"location.href='https://www.mydomain.com/shop/bags?cid=Black'", "onclick=\"location.href='https://www.mydomain.com/shop/bags?cid=Beige'", "onclick=\"location.href='https://www.mydomain.com/shop/bags?cid=Green'" }; final Pattern pattern = Pattern.compile("(\\Qhttps://www.mydomain.com/shop/bags\\E)\\?cid=[^']++"); for(final String string : in) { final Matcher m = pattern.matcher(string); final String replaced = m.replaceAll("$1SOMETHING_ELSE"); System.out.println(replaced); } } </code></pre> <p>Output:</p> <pre><code>onclick="location.href='https://www.mydomain.com/shop/bagsSOMETHING_ELSE' onclick="location.href='https://www.mydomain.com/shop/bagsSOMETHING_ELSE' onclick="location.href='https://www.mydomain.com/shop/bagsSOMETHING_ELSE' </code></pre>
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    1. POUse regex to find a phrase with symbols in an URL
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    1. USBoris the Spider
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    1. COI tried this and unfortunately I don't think the program supports this, any other solution? Sorry for the inconvenience
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