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POTwo questions regarding regular expressions
 

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  1. POTwo questions regarding regular expressions
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    <p>I currently use this:</p> <pre><code>$text = preg_replace('/' . $line . '/', '[x]\\0[/x]', $text); </code></pre> <p><code>$line</code> is a simple regular expression:</p> <pre><code>https?://(?:.+?\.)?dailymotion\.com/video/[A-Za-z0-9]+ </code></pre> <p>This is working fine so far. But there are two things that I need and I can't figure out, how to do that:</p> <p>... I don't want to perform the replacement, if that string is contained within a <code>BBCode</code> i.e.</p> <blockquote> <p>[bla]http://www.dailymotion.com/video/xuams9[/bla]</p> </blockquote> <p>or</p> <blockquote> <p>[bla=http://www.dailymotion.com/video/xuams9]trololo[/bla]</p> </blockquote> <p>or</p> <blockquote> <p>[bla='<a href="http://www.dailymotion.com/video/xuams9" rel="nofollow">http://www.dailymotion.com/video/xuams9</a>']http://www.dailymotion.com/video/xuams9[/bla]</p> </blockquote> <p>The 2nd thing is, that I just want to match until the first space. This is what I currently use:</p> <pre><code>$text = preg_replace('/' . $line . '(?:[^ ]+)?/', '[x]\\0[/x]', $text); </code></pre> <p>I don't know, if I should do it like this or if there's a better way.</p> <p>So, basically i'm just trying to match</p> <blockquote> <p><a href="http://www.dailymotion.com/video/test4" rel="nofollow">http://www.dailymotion.com/video/test4</a></p> </blockquote> <p>from this:</p> <p><code>[tagx='http://www.dailymotion.com/video/test1']http://www.dailymotion.com/video/test2[/tagx] | [tagy]Hello http://www.dailymotion.com/video/test3 World[/tagy] | [tagz]Hello World[/tagz] http://www.dailymotion.com/video/test4</code></p> <p>EDIT:</p> <p>This is, what i have so far (which works slightly):</p> <p><code>(?:(?&lt;!(\[\/url\]|\[\/url=))(\s|^))' . $line . '(?:[^ ]+)(?:(?&lt;![[:punct:]])(\s|\.?$))?</code></p>
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    1. COHow does that regex work? You're using your delimiter `/` unescaped in the pattern: `https?://`
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    2. CO`$regex = str_replace('/', '\\/', $regex);`
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    3. COYou can use `\S` to match string until first blank-space character.
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