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    <p>Here is how I would write it. The first query gets all keywords that must be in all 4 projects 1, 2, 3 and 4 via qualifier of project 1 keywords and JOIN to other for 2, 3 and 4. If you want a minimum of project 1 and ANY of 2, 3 or 4, I would change it slightly.</p> <p>From that, only then join to results and to the years table. Now, to help on optimization. Your keywords table should have an index on ( id, projects_id ). Results table should have an index on (keywords_id, country, user ) -- the country and user to help in the group by.</p> <pre><code>select STRAIGHT_JOIN r.country, r.user, SUM( y.january + y.february + y.march + y.april + y.may + y.june + y.july + y.august + y.september + y.october + y.november + y.december ) as AllMonths from ( SELECT k.id FROM keywords k JOIN keywords k2 on k.id = k2.id AND k2.project_id = 2 JOIN keywords k3 on k.id = k3.id AND k3.project_id = 3 JOIN keywords k4 on k.id = k4.id AND k4.project_id = 4 where k.project_id = 1 ) KeywordsInAll JOIN results r ON KeywordsInAll.ID = r.keywords_id JOIN `year` y ON r.id = y.results_id group by r.country, r.user </code></pre> <p>I changed the inner query to START with keywords AT LEAST from project 1... No sense in querying 10,000 keywords if project 1 only has 15 keywords (exaggerated, but example)</p> <p>From your posted comment, I would just change the prequery to almost exact as yours, but keep in first position and retain the "STRAIGHT_JOIN"</p> <pre><code> ( SELECT DISTINCT k.id FROM keywords k JOIN keywords k2 on k.id = k2.id AND k2.project_id IN (2, 3, 4 ) where k.project_id = 1 ) KeywordsInAll </code></pre>
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    1. CO@jon, I revised answer... I would keep similar distinct keyword.
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    2. COgreat, that did it. I had to change the ON clause in the subquery to compare k.keyword = k2.keyword since all the ids are different. But it is working a fine now. Thanks a lot.
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