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2013-05-29T10:11:48.887
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<p>I investigated the issue and it seems like Denis is right. From looking at the class <code>Index</code> from the current hibernate implementation (cf. <a href="https://github.com/hibernate/hibernate-orm/blob/master/hibernate-core/src/main/java/org/hibernate/mapping/Index.java%5d" rel="nofollow">1</a>), it becomes clear that specification of index types is not supported, yet.</p> <pre class="lang-java prettyprint-override"><code>public static String buildSqlCreateIndexString( Dialect dialect, String name, Table table, Iterator<Column> columns, java.util.Map<Column, String> columnOrderMap, boolean unique, String defaultCatalog, String defaultSchema ) { StringBuilder buf = new StringBuilder( "create" ) .append( unique ? " unique" : "" ) .append( " index " ) .append( dialect.qualifyIndexName() ? name : StringHelper.unqualify( name ) ) .append( " on " ) .append( table.getQualifiedName( dialect, defaultCatalog, defaultSchema ) ) .append( " (" ); while ( columns.hasNext() ) { Column column = columns.next(); buf.append( column.getQuotedName( dialect ) ); if ( columnOrderMap.containsKey( column ) ) { buf.append( " " ).append( columnOrderMap.get( column ) ); } if ( columns.hasNext() ) buf.append( ", " ); } buf.append( ")" ); return buf.toString(); } </code></pre> <p>The most simple workaround is to call <code>session.createSQLQuery()</code> and to issue <code>CREATE INDEX</code> yourself. This however, is a database-specific operation that needs to be maintained by the applications developer (in case the database is changed).</p>
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