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POCannot insert into table. PHP/MySQL
 

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  1. POCannot insert into table. PHP/MySQL
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    <p>I have a table named 'Directors' in the database 'db2'. I have an HTML form. I would like when I insert the values and hit submit button, to insert the content into the table in a new row (to INSERT INTO), after it makes some validations (you'll notice them in the script). I've tried to do it by myself, but it is always echoing me 'Fail'; This is my HTML form:</p> <pre><code> &lt;form action="process.php" method="post" accept-charset="utf-8"&gt; &lt;input type="hidden" name="pages_edit_nonce" /&gt; &lt;div class="section-item page-title-section"&gt; &lt;label for="title"&gt;Full Name:&lt;/label&gt;&lt;span class="help"&gt;*&lt;/span&gt;&lt;div class="input-wrap"&gt;&lt;input type="text" name="name" value="" /&gt;&lt;/div&gt; &lt;/div&gt; &lt;div class="section-item"&gt; &lt;label for="label"&gt;Phone:&lt;/label&gt;&lt;span class="help"&gt;*Optionally&lt;/span&gt;&lt;div class="input-wrap"&gt;&lt;input type="text" name="phone" value="" /&gt;&lt;/div&gt; &lt;/div&gt; &lt;div class="section-item"&gt; &lt;label for="redirect"&gt;Е-mail:&lt;/label&gt;&lt;span class="help"&gt;*&lt;/span&gt;&lt;div class="input-wrap"&gt;&lt;input type="text" name="email" value="" placeholder="" /&gt;&lt;/div&gt; &lt;/div&gt; &lt;div class="section-item"&gt; &lt;label for="redirect"&gt;School:&lt;/label&gt;&lt;span class="help"&gt;*&lt;/span&gt;&lt;div class="input-wrap"&gt;&lt;input type="text" name="school" value="" placeholder="" /&gt;&lt;/div&gt; &lt;/div&gt; &lt;div class="section-item"&gt; &lt;label for="redirect"&gt;City:&lt;/label&gt;&lt;span class="help"&gt;*&lt;/span&gt;&lt;div class="input-wrap"&gt;&lt;input type="text" name="city" value="" placeholder="" /&gt;&lt;/div&gt; &lt;/div&gt; &lt;div class="section-item"&gt; &lt;label for="redirect"&gt;Password:&lt;/label&gt;&lt;span class="help"&gt;*&lt;/span&gt;&lt;div class="input-wrap"&gt;&lt;input type="password" name="password" value="" placeholder="" /&gt;&lt;/div&gt; &lt;/div&gt; &lt;div class="admin-bar"&gt; &lt;div class="admin-bar-inner"&gt; &lt;input type="submit" value="Submit" class="btn" /&gt; &lt;/div&gt; &lt;/div&gt; &lt;/form&gt; </code></pre> <p>This is my process.php file:</p> <pre><code>$server = "localhost"; $user = "****"; $pass = "****"; $conn = mysql_connect($server, $user, $pass); $db = mysql_select_db("****", $conn); session_start(); if(!$db) { $_SESSION['ERRMSG'] = "&lt;strong&gt;Error:&lt;/strong&gt; The access to the database is denied!"; header("Location: ../../admin/error/"); exit(); } session_start(); function UniqueID() { $UID = rand(); //Create unique ID $check = mysql_query("SELECT * FROM `Directors` WHERE `UID` = '$UID'"); if(mysql_num_rows($check) &gt; 0) { //Check if it exists UniqueID(); //Redo the function } else { return $UID; //return the uniqueid } } $UID = UniqueID(); //Unique ID $email = $_POST['email']; $password = $_POST['password']; $name = $_POST['name']; $phone = $_POST['phone']; $school = $_POST['school']; $city = $_POST['city']; //Create INSERT query $qry = "INSERT INTO `oclass`.`Directors`(`UID`,`Name`, `Phone`, `Email`, `SchoolGymnasium`, `City`, `Password`) VALUES('$UID','$name','$phone','$email','$school','$city','" . md5($password) . "')"; $result = mysql_query($qry); //Check whether the query was successful or not if($result) { $_SESSION['SUCCMSGADDDIR'] = 'Sucessful.'; header("location: URL"); exit(); } else { $_SESSION['ERRMSGADDDIR'] = 'Fail'; header("location: URL"); } </code></pre> <p>After changing the error session with mysql_error() it gave me the following error: Fatal error: Can't use function return value in write context in ... on line 10; Line 10 is:</p> <pre><code>mysql_error() = "&lt;strong&gt;Error:&lt;/strong&gt; The access to the database is denied!"; </code></pre> <p>I've removed the column named ID (which was Primary Key) and set UID column as Primary Key, and now is working. Thank you guys.</p>
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    1. This table or related slice is empty.
    1. This table or related slice is empty.
    1. PTQuestion
    1. USHoxo Dimirat
    1. USHoxo Dimirat
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    1. This table or related slice is empty.
    1. This table or related slice is empty.
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    1. This table or related slice is empty.
    1. COIf you're getting "Fail" all the time it means that the condition if($result) is returning false, which means that $result is not a valid resource in this case caused by a bad query ( mysql error ). Echo mysql_error and see what you're getting.
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      1. POCannot insert into table. PHP/MySQL
      1. USphp_nub_qq
    2. COConsider using `PDO` or `mysqli` and not `mysql_*`. Anyway , in order to debug the query , change the value of the failed session to: `mysql_error()` and share the output.
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      1. POCannot insert into table. PHP/MySQL
      1. USOfir Baruch
    3. COto change $_SESSION['SUCCMSGADDDIR'] with mysql_error() ?
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      1. POCannot insert into table. PHP/MySQL
      1. USHoxo Dimirat
 

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