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POHow to concurrently process spring integration jms channels
 

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  1. POHow to concurrently process spring integration jms channels
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    <p>I've got a JMS connectionFactory that a number of spring integration jms inbound-gateways use. They work fine, but only one message at a time. I'd like to make them handle N concurrent messages at a time in different threads. </p> <p>The code I've got now is as follows.</p> <p>spring-config.xml</p> <pre><code>&lt;import resource="commons/jmsConnectionFactory.xml"/&gt; &lt;import resource="chain/chain1.xml"/&gt; &lt;import resource="chain/chain2.xml"/&gt; </code></pre> <p>jmsConnectionFactory.xml</p> <pre><code>&lt;bean id="connectionFactory" class="org.apache.activemq.ActiveMQConnectionFactory"&gt; &lt;property name="brokerURL"&gt; &lt;value&gt;failover:(tcp://mqmaster:61616,tcp://mqslave:61616)?jms.prefetchPolicy.all=1&amp;amp;randomize=false&lt;/value&gt; &lt;/property&gt; &lt;/bean&gt; </code></pre> <p>chains all look something like this</p> <pre><code>&lt;int:channel id="fooChannel"/&gt; &lt;int-jms:inbound-gateway request-channel="fooChannel" request-destination-name="foo" extract-request-payload="true" /&gt; &lt;int:chain input-channel="fooChannel"&gt; &lt;int-http:outbound-gateway url="...." http-method="GET" extract-request-payload="true" /&gt; &lt;int:object-to-string-transformer /&gt; &lt;/int:chain&gt; </code></pre> <p>I know that I can add "concurrent-consumers" and "max-concurrent-consumers" to the inbound-gateway to make the gateway process multiple messages. That would result though in having each chain/gateway handling it's threads managed independently. I would like some way to define a common thread pool for everyone using the JMS connection. This would allow me to specify 5 threads and have them allocated among the gateways based on what messages the server is supplying, but constraining the consuming server to a manageable amount of work.</p> <p>What modifications are needed to do the processing with multiple threads? And how do I limit the number of threads?</p>
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