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16717731
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2013-05-23T15:17:37.203
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2013-05-23T15:29:05.790
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2013-05-23T15:29:05.790
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Remove the <code>/src</code> from your path. Assuming <code>src</code> is on your build path (in your IDE), then the compiled code will contain only the folders inside it directly at the root. For example, <pre><code>/src /main/resources file.txt </code></pre> will produce <pre><code>/main/resources/file.txt </code></pre> Now if <code>/src/main/resources</code> in on the buildpath, you need to remove the whole thing and the file will appear on the root. Its <code>InputStream</code> would be accessible as <pre><code>InputStream in = this.getClass().getResourceAsStream("/<folder name here>/<file name here>.txt"); </code></pre> Example <pre><code>/src/main/resources // buildpath /spring applicationContext.xml /src/main/java // buildpath /mypackage MyClass.java </code></pre> would be accessible like <pre><code>InputStream in = this.getClass().getResourceAsStream("/spring/applicationContext.xml"); </code></pre> which means the jar (if that's how you compiled and packaged it) would be structured as <pre><code>/spring applicationContext.xml /mypackage MyClass.class </code></pre> The method <code>getResourceAsStream(String)</code> <a href="http://docs.oracle.com/javase/7/docs/api/java/lang/Class.html#getResourceAsStream%28java.lang.String%29" rel="nofollow">javadoc</a> says: <blockquote> <ul> <li>If the name begins with a '/' ('\u002f'), then the absolute name of the resource is the portion of the name following the '/'. </li> <li>Otherwise, the absolute name is of the following form: modified_package_name/name </li> </ul> Where the modified_package_name is the package name of this object with '/' substituted for '.' ('\u002e'). </blockquote>
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1. POHow to read from text files in classpath across directories?
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1. USSotirios Delimanolis
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1. USSotirios Delimanolis
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