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    <p>This is the final result. It's a little more robust than my initial effort; it properly escapes sub-expressions, makes sure they appear in the right order and doesn't stop when it finds an empty one: </p> <pre><code>/** * Constructs a regular expression to restore tainted RegExp properties */ function createRegExpRestore () { var lm = RegExp.lastMatch, ret = { input: RegExp.input }, esc = /[.?*+^$[\]\\(){}|-]/g, reg = [], cap = {}; // Create a snapshot of all the 'captured' properties for (var i = 1; i &lt;= 9; i++) cap['$'+i] = RegExp['$'+i]; // Escape any special characters in the lastMatch string lm = lm.replace(esc, '\\$0'); // Now, iterate over the captured snapshot for (var i = 1; i &lt;= 9; i++) { var m = cap['$'+i]; // If it's empty, add an empty capturing group if (!m) lm = '()' + lm; // Else find the escaped string in lm wrap it to capture it else lm = lm.replace(m.replace(esc, '\\$0'), '($0)'); // Push to `reg` and chop `lm` reg.push(lm.slice(0, lm.indexOf('(') + 1)); lm = lm.slice(lm.indexOf('(') + 1); } // Create the property-reconstructing regular expression ret.exp = RegExp(reg.join('') + lm, RegExp.multiline ? 'm' : ''); return ret; } </code></pre> <p>It does what I originally thought to be difficult. This should restore all the properties to their former values, if you use it like so:</p> <pre><code>var // Create a 'restore point' for RegExp old = createRegExpRestore(), // Run your own regular expression test = someOtherRegEx.test(someValue); // Restore the previous values by running the RegExp old.exp.test(old.input); </code></pre>
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