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POIs it possible to legally overload a string literal and const char*?
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16708307
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2013-05-23T07:44:13.823
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2013-05-23T09:00:43.013
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2013-05-23T07:50:42.287
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Is it possible in C++11 to overload <code>const char*</code>'s and string literals (<code>const char[]</code>)? The idea is to avoid having to call <code>strlen</code> to find the string length when this length is known already. This snippet breaks on G++ 4.8 and Clang++ 3.2: <pre><code>#include <stdio.h> #include <stdlib.h> #include <string.h> template<typename T, int N> void length(const T(&data)[N]) { printf("%u[]\n", N - 1); } template<typename T> void length(const T* data) { printf("*%u\n", (unsigned)strlen(data)); } int main() { length("hello"); const char* p = "hello"; length(p); return 0; } </code></pre> Error (Clang): <pre><code>test2.cpp:16:3: error: call to 'length' is ambiguous length("hello"); ^~~~~~ test2.cpp:6:6: note: candidate function [with T = char, N = 6] void length(const T(&data)[N]) { ^ test2.cpp:11:6: note: candidate function [with T = char] void length(const T* data) { ^ 1 error generated. </code></pre> Hacked a bit, and this appears to work: <pre><code>#include <stdio.h> #include <stdlib.h> #include <string.h> template<typename T, int N> void length(const T(&data)[N]) { printf("%u[]\n", N - 1); } template<typename T> void length(T&& data) { printf("*%u\n", (unsigned)strlen(data)); } const char *foo() { return "bar"; } int main() { length("hello"); const char* p = "hello"; length(p); length(foo()); return 0; } </code></pre> Is this valid C++11? The string literal appears to overload on <code>T&&</code> when the array specialization is removed. What causes this ambigousness to be resolved, but not the one in the first code snippet?
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<c++><templates><c++11><overloading>
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Is it possible to legally overload a string literal and const char*?
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