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2013-05-20T20:39:45.557
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You are missing the idea of a context node. Within a <code>xsl:for-each</code>, everything you refer to is about or relative to the selected nodes. So, for instance, within <code><xsl:for-each select="News/Sport"></code>, the context node is the <code>Sport</code> elements, and a test like <code><xsl:if test="local-name()='Basketball'"></code> is always going to be false because the local name is always <code>Sport</code>. It looks like you want just <code><xsl:if test="Basketball"></code> which tests whether there are any <code>Basketball</code> child nodes of the current <code>Sport</code> node. The same thing applies to <code><xsl:value-of select="News/Sport/Basketball/Phrases/Phrase"/></code>. Because everything is relative to the <code>Sport</code> node, XSLT is looking for <code>News/Sport/Basketball/Phrases/Phrase</code> within the <code>Sport</code> element, which never exists. In addition, you can just put text in literally: there is no need for an <code>xsl:text</code> element here, so your code should look like <pre><code><xsl:for-each select="News/Sport"> <xsl:if test="Basketball"> Basketball Sport <xsl:value-of select="Basketball/Phrases/Phrase"/> </xsl:if> </xsl:for-each> </code></pre> You can refine this further by adding a predicate to the <code>for-each</code> selection, so that it matches only <code>Sport</code> elements with a <code>Basketball</code> child. Like this <pre><code><xsl:for-each select="News/Sport[Basketball]"> Basketball Sport <xsl:value-of select="Basketball/Phrases/Phrase"/> </xsl:for-each> </code></pre>
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1. POHow to make XSLT xsl:if work
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