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POMultiply audio signals for robot voice C#
 

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  1. POMultiply audio signals for robot voice C#
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    <p>I'm trying to get the wave output of .NET SpeechSynthesizer to make the voice sound like robot-ish. </p> <p>After some research, I have found that ring modulation might be a good option to obtain the effect I want. I have seen that the formula is basically <code>Result(t) = Voice(t) * SineWave(t)</code>. </p> <p>Although, I have no idea of how I could apply this effect from a Wave Stream, is there any library out there to :</p> <ul> <li>Generate a sine wave and process it into a Wave Stream</li> <li>Multiply both Streams in order to get the result</li> </ul> <p>If not, do you know any other option ? Maybe I could multiply each sample in the Voice Wave Stream by each sample in the sine wave ?</p> <p>I'm using C# /.net framework.</p> <p>Thank you !</p> <p><strong>Edit :</strong> Okay, so after a few hours of failed attempts, I've finally came up with what seems to be the good result. The only problem is that there's a lot of crackling on the output, and the only fix I've found is to apply a low pass filter.</p> <p>Here's what I've got so far (quick, dirty and uncommented code, but should be self explanatory):</p> <pre><code>class Mixer { public static Stream RingModulation(Stream voiceStream, TimeSpan duration, SpeechAudioFormatInfo format) { var sineWave = SineOscillator.GenerateWave(duration, 80, 1, format); var numSamples = Convert.ToInt32(duration.TotalSeconds * format.SamplesPerSecond); var dataStream = new MemoryStream(); sineWave.Position = 0; voiceStream.Position = 0; var buf1 = new byte[2]; var buf2 = new byte[2]; for (var i = 0; i &lt; numSamples; i++) { voiceStream.Read(buf1, 0, 2); sineWave.Read(buf2, 0, 2); var data = BitConverter.GetBytes(Convert.ToInt16(BitConverter.ToInt16(buf1, 0) * BitConverter.ToInt16(buf2, 0))); dataStream.Write(data, 0, data.Length); } return dataStream; } } class SineOscillator { public static Stream GenerateWave(TimeSpan duration, double frequency, int amplitude, SpeechAudioFormatInfo format) { var numSamples = Convert.ToInt32(duration.TotalSeconds * format.SamplesPerSecond); var dataStream = new MemoryStream(); var angle = (Math.PI * 2 * frequency) / (format.SamplesPerSecond * format.ChannelCount); for (var i = 0; i &lt; numSamples; i++) { var data = BitConverter.GetBytes(Convert.ToInt16(amplitude * Math.Sin(angle*i))); // Generate a sine wave in both channels. dataStream.Write(data, 0, data.Length); } return dataStream; } } </code></pre> <p>The low pass filter isn't applied yet, although, questions are still open in case someone has a good answer to provide and/or a better way to do it :)</p>
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    1. USAnthony Teisseire
    1. USAnthony Teisseire
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    1. COare you aware that this sine(t) will = 0 in some times?
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      1. USMokhtar Ashour
    2. COI know it will, but afaik, it's the way Ring modulation works
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      1. USAnthony Teisseire
 

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