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POphoto not displaying after making php call
 

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  1. POphoto not displaying after making php call
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    <p>I am trying to retrieve some data from a database using php, then I add the data inside json_encode array to be sent to my other php file so that the contents could be displayed on a site. currently I am able to retrieve contents that contain text however, I am unable to retrieve the images. For example instead of displaying an image of London, the text London..jpg is displayed. </p> <p>Here is my php file that selects the data for the data base</p> <pre><code> &lt;?php require_once('conn.inc.php'); $stmt = $mysqli-&gt;prepare("SELECT CityName,CityID, CityPopulation,CitySkills,CityEmploymentRates,CityjsaClaimants ,Image ,CityWeeklyEarnings FROM citiesdata WHERE CityID = ? ORDER BY CityName"); $stmt-&gt;bind_param('i', $_GET['CityID']); $stmt-&gt;execute(); $stmt-&gt;bind_result($CityName, $CityID,$CityPopulation,$CitySkills,$CityEmploymentRates,$CityjsaClaimants,$Image,$CityWeeklyEarnings); $myArray = array(); while ($stmt-&gt;fetch()) { $myArray[] = $CityName; $myArray[] = $CityPopulation; $myArray[] = $CitySkills; $myArray[] = $CityEmploymentRates; $myArray[] = $CityjsaClaimants; $myArray[] = $Image; $myArray[] = $CityWeeklyEarnings; } echo json_encode($myArray); ?&gt; </code></pre> <p>And here is the javascript code I am using to retrieve the data in to my website, I am retrieving the data using CityID for example if CityID is 1 a radio button is clicked with value 1 this will match the CityID of 1 which is London and the details of the city will be displayed except the image since I have multiple images I have used json_encode I have no idea where to put the image src since I am working with multiple cities with multiple images. Everything is displayed fine on the website the cityName,Cityskills etc when the user selects a city via a radio button, how can I make it so that when the user selects the radio button the city images will be displayed alongside the cityNames, city skills etc?</p> <pre><code>$(document).ready(function(){ $('input[name=CityID]').on('click', function(){ var sendVals = $(this).serialize(); var returnData = ""; $("#displayResults").html('&lt;li&gt;Please Wait!&lt;/li&gt;'); $.get("phpCalling.php", sendVals, function(myData){ $.each(myData, function(key, value) { returnData += "&lt;p&gt;" returnData += value; returnData += "&lt;/p&gt;"; }) $("#displayResults").html(returnData); }, "json"); }); }); </code></pre>
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    1. USSky
    1. USSky
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    1. COAren't you just outputting the link with your method? It needs to be added as an image `<img src='var should be here'>`
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      1. USbrbcoding
    2. COHow are you storing the image in the database? Are you storing the image itself as a `blob` or just its filepath?
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      1. POphoto not displaying after making php call
      1. USJosh Balcitis
    3. CO@JoshBalcitis, I am storing the Image as London.jpg without the filepath
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      1. USSky
 

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