StackOverflow2013

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plurals

PO
primarykey
Id
1657729
data
AcceptedAnswerId
0
AnswerCount
0
ClosedDate
CommentCount
2
CommunityOwnedDate
CreationDate
2009-11-01T17:27:06.307
FavoriteCount
0
LastActivityDate
2009-11-02T15:39:06.540
LastEditDate
2009-11-02T15:39:06.540
LastEditorUserId
88622
OwnerUserId
88622
ParentId
1583989
PostTypeId
2
Score
3
ViewCount
0
LastEditorDisplayName
text
Body
You can do better without list reversal. WLOG I'll assume that both lists have equal length (prepend with 0 if necessary). Start the addition from left to right (from most significant to least significant digit). You have three cases, depending of the sum of two digits: <ol> <li>= 9: keep the nine and increase a <code>counter</code></li> <li>< 9: write <code>counter</code> x nine, write sum, reset <code>counter</code></li> <li><blockquote> 9: increase last digit, write <code>counter</code> x zero, write sum (modulo 10), reset counter </blockquote></li> </ol> I'll work on the following example: <pre><code>2 568 794 + 1 438 204 --------- = 4 006 998 </code></pre> <ol> <li>Add <code>2 + 1 = 3</code>: case 3. <ul> <li><code>list = (3)</code>, <code>counter = 0</code></li> </ul></li> <li>Add <code>5 + 4 = 9</code>: case 1 <ul> <li><code>list = (3)</code>, <code>counter = 1</code></li> </ul></li> <li>Add <code>6 + 4 = 9</code>: case 1 <ul> <li><code>list = (3)</code>, <code>counter = 2</code></li> </ul></li> <li>Add <code>8 + 8 = 16</code>: case 3 <ul> <li><code>list = (4, 0, 0, 6)</code>, <code>counter = 0</code></li> </ul></li> <li>Add <code>7 + 2 = 9</code>: case 1 <ul> <li><code>list = (4, 0, 0, 6)</code>, <code>counter = 1</code></li> </ul></li> <li>Add <code>9 + 0 = 9</code>: case 1 <ul> <li><code>list = (4, 0, 0, 6)</code>, <code>counter = 2</code></li> </ul></li> <li>Add <code>4 + 4 = 8</code>: case 2 <ul> <li><code>list = (4, 0, 0, 6, 9, 9, 8)</code>, <code>counter = 0</code></li> </ul></li> </ol>
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1. This table or related slice is empty.
PostParentId
1. POMost optimal way to find the sum of 2 numbers represented as linked lists
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1. PTAnswer
UserLastEditorUserId
1. USAlexandru
UserOwnerUserId
1. USAlexandru
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VotesPostIdCreationDate
1. VO
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CommentsPostId
1. COThats great, but how will this method work for unequal length lists?
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2. COYou still need to know the sizes of the list and make them the equal by prepending 0 to the shorter (or, put the first m - n elements (m > n) in the final list).
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 USAlexandru

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