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    <p>You'll have to handle the code yourself (I'm a Java developer), but the simplest way to get the angle between two points on a circle (measured against its center) is to recall the geometry of the situation. The triangle formed by any two points on the circumference of a circle and the circle's center is necessarily <a href="http://mathworld.wolfram.com/IsoscelesTriangle.html" rel="nofollow">isosceles</a>.</p> <p>An isosceles triangle, recall, has (at least) two sides of the same length -- the radial segments to your two points. Bisecting the angle results in a radial segment which is perpendicular to and bisects the line connecting the two points. This forms a pair of right triangles, with the radius as the hypotenuse, and half the distance between the two points as the 'opposite' side.</p> <p>Moving the factor of two to the denominator and recognizing what twice the radius is, simply calculate the distance between the two points (on the circumference), and divide it by the diameter. The value you get is the sine of the half-angle (you desire the whole angle). Take the arcsine, and you'll have half your angle:</p> <p><em>θ/2 = sin<sup>-1</sup>(d/D)</em></p> <p>With <code>d</code> as the distance between the two points, and <code>D</code> as the diameter of the circle. Since the diameter is given, and the distance between the two points is <a href="http://cs.selu.edu/~rbyrd/math/distance/" rel="nofollow">simple to calculate</a>, getting to this point should be easy, and then you just need to double the value calculated to get the whole angle between the two points.</p>
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