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POFinding variants of a string (only deletion, no transposition)
 

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    <p>Given a string, I want to find all variants without transposition, only deletion. For example, given the string:</p> <pre><code>helloo </code></pre> <p>The list of variants would be as follows (separated by white space).</p> <pre><code>helloo hello heloo helo </code></pre> <p>My solution so far is to move through each character, and then if the current character matches the next character, recursively try the original and the deleted character version, as follows.</p> <pre><code>// takes String with at most two consecutive characters of any character, // and returns an Iterable of all possible variants (e.g. hheello -&gt; heello, hhello, ...) private static Iterable&lt;String&gt; findAllVariants(String word) { StringBuilder variant = new StringBuilder(word); Queue&lt;String&gt; q = new LinkedList&lt;String&gt;(); findAllVariants(word, variant, 0, q); return q; } // helper method private static void findAllVariants(String word, StringBuilder variant, int currIndex, Queue&lt;String&gt; q) { if (currIndex == variant.length() - 1) q.add(variant.toString()); for (int i = currIndex; i &lt; variant.length() - 1; i++) { char thisChar = variant.charAt(i); char nextChar = variant.charAt(i+1); if (thisChar == nextChar) { // get all variants with repeat character findAllVariants(word, variant, i+1, q); // get all variants without repeat character; variant = variant.deleteCharAt(i); findAllVariants(word, variant, i, q); } } } </code></pre> <p>However, I end up getting a large number of copies of answers, and none of others. When I do my algorithm on paper, it seems correct. What am I doing wrong?</p>
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