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POCan I access the __dict__ object for the local scope?
 

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    <p>Here is my situation...</p> <p>I am trying to dynamically generate a bunch of stuff in my settings.py file on a django site.</p> <p>I am setting up several sites, (via sites framework) and I want to have some values I plug in to a function that will generate a portion of the settings file for each site.</p> <p>for example:</p> <pre><code>from universal_settings import * SITE_NAME = 'First Site' SITE_SLUG = 'firstsite' DEFAULT_FROM_EMAIL = '%s &lt;noreply@otakupride.com&gt;' % SITE_NAME ROOT_URLCONF = 'mysite.urls.%s' % SITE_SLUG TEMPLATE_DIRS += ( os.path.join(PROJECT_ROOT, "templates", SITE_SLUG), ) </code></pre> <p>obviously it's a huge violation of DRY to have those last 3 lines in the settings file for every site running this code. So I want to do something like this</p> <pre><code>from universal_settings import * from utils import get_dynamic_settings SITE_NAME = 'First Site' SITE_SLUG = 'firstsite' get_dynamic_settings( locals() ) </code></pre> <p>And here is the function</p> <pre><code># WARNING: THIS CODE DOES NOT WORK! def get_dynamic_settings(context_dict): global DEFAULT_FROM_EMAIL global ROOT_URLCONF global TEMPLATE_DIRS DEFAULT_FROM_EMAIL = '%s &lt;noreply@otakupride.com&gt;' % context_dict['SITE_NAME'] ROOT_URLCONF = 'mysite.urls.%s' % context_dict['SITE_SLUG'] TEMPLATE_DIRS += ( os.path.join(PROJECT_ROOT, "templates", context_dict['SITE_SLUG']), ) </code></pre> <p>so my question is... how do I add things to the scope of the settings file? it doesn't seem to have a <strong>dict</strong> object available to the variables within it.</p> <p>Maybe I'm going about this all wrong? Thanks for your help!</p> <p>PS - my understanding of the <code>global</code> keyword is that it tells the compiler that the function means to manipulate a global variable <strong>within it's own file</strong> - is there such a thing for the file which the function is called?</p>
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