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    <p>Had more of a play. Can't get it to work using the user variables due to the ordering of items.</p> <p>However if you have a reasonable maximum number of levels then you can do something like this:-</p> <pre><code>SELECT CONCAT_WS('-', a.allCols, b.allCols, c.allCols, d.allCols, e.allCols, f.allCols, g.allCols, h.allCols, i.allCols, j.allCols, k.allCols, l.allCols, m.allCols) FROM (SELECT col1, col3, CONCAT(col1, col2, col3) AS allCols FROM table1) a LEFT OUTER JOIN(SELECT col1, col3, CONCAT(col1, col2, col3) AS allCols FROM table1) b ON a.col3 = b.col1 LEFT OUTER JOIN(SELECT col1, col3, CONCAT(col1, col2, col3) AS allCols FROM table1) c ON b.col3 = c.col1 LEFT OUTER JOIN(SELECT col1, col3, CONCAT(col1, col2, col3) AS allCols FROM table1) d ON c.col3 = d.col1 LEFT OUTER JOIN(SELECT col1, col3, CONCAT(col1, col2, col3) AS allCols FROM table1) e ON d.col3 = e.col1 LEFT OUTER JOIN(SELECT col1, col3, CONCAT(col1, col2, col3) AS allCols FROM table1) f ON e.col3 = f.col1 LEFT OUTER JOIN(SELECT col1, col3, CONCAT(col1, col2, col3) AS allCols FROM table1) g ON f.col3 = g.col1 LEFT OUTER JOIN(SELECT col1, col3, CONCAT(col1, col2, col3) AS allCols FROM table1) h ON g.col3 = h.col1 LEFT OUTER JOIN(SELECT col1, col3, CONCAT(col1, col2, col3) AS allCols FROM table1) i ON h.col3 = i.col1 LEFT OUTER JOIN(SELECT col1, col3, CONCAT(col1, col2, col3) AS allCols FROM table1) j ON i.col3 = j.col1 LEFT OUTER JOIN(SELECT col1, col3, CONCAT(col1, col2, col3) AS allCols FROM table1) k ON j.col3 = k.col1 LEFT OUTER JOIN(SELECT col1, col3, CONCAT(col1, col2, col3) AS allCols FROM table1) l ON k.col3 = l.col1 LEFT OUTER JOIN(SELECT col1, col3, CONCAT(col1, col2, col3) AS allCols FROM table1) m ON l.col3 = m.col1 WHERE a.col1 = 1 </code></pre> <p>This is coping with up to 13 levels (OK, only a couple used in your test data), and will give a comma separated bit for each column, with each row joined with a dash (-).</p>
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    1. PO@ Symbol - a solution for Recursive SELECT query in Mysql?
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    1. COBut the number of the links is unknown, ie it could have only 3 links or 5 links or 20 links
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    2. CODoesn't matter, as long as you have at least as many joins. You say there are only 20~30 links, so that should be easily covered with this.
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    3. COI sticked with Gordon's solution. Thank you anyway.
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