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    <p>My original answer is outdated. If I would have to build it again i would use xmlunit 2 and xmlunit-matchers. Please note that for xml unit a different order is always 'similar' not equals.</p> <pre><code>@Test public void testXmlUnit() { String myControlXML = "&lt;test&gt;&lt;elem&gt;a&lt;/elem&gt;&lt;elem&gt;b&lt;/elem&gt;&lt;/test&gt;"; String expected = "&lt;test&gt;&lt;elem&gt;b&lt;/elem&gt;&lt;elem&gt;a&lt;/elem&gt;&lt;/test&gt;"; assertThat(myControlXML, isSimilarTo(expected).withNodeMatcher(new DefaultNodeMatcher(ElementSelectors.byNameAndText))); //In case you wan't to ignore whitespaces add ignoreWhitespace().normalizeWhitespace() assertThat(myControlXML, isSimilarTo(expected).ignoreWhitespace().normalizeWhitespace().withNodeMatcher(new DefaultNodeMatcher(ElementSelectors.byNameAndText))); } </code></pre> <p>If somebody still want't to use a pure java implementation here it is. This implementation extracts the content from xml and compares the list ignoring order.</p> <pre><code>public static Document loadXMLFromString(String xml) throws Exception { DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance(); DocumentBuilder builder = factory.newDocumentBuilder(); InputSource is = new InputSource(new StringReader(xml)); return builder.parse(is); } @Test public void test() throws Exception { Document doc = loadXMLFromString("&lt;test&gt;\n" + " &lt;elem&gt;b&lt;/elem&gt;\n" + " &lt;elem&gt;a&lt;/elem&gt;\n" + "&lt;/test&gt;"); XPathFactory xPathfactory = XPathFactory.newInstance(); XPath xpath = xPathfactory.newXPath(); XPathExpression expr = xpath.compile("//test//elem"); NodeList all = (NodeList) expr.evaluate(doc, XPathConstants.NODESET); List&lt;String&gt; values = new ArrayList&lt;&gt;(); if (all != null &amp;&amp; all.getLength() &gt; 0) { for (int i = 0; i &lt; all.getLength(); i++) { values.add(all.item(i).getTextContent()); } } Set&lt;String&gt; expected = new HashSet&lt;&gt;(Arrays.asList("a", "b")); assertThat("List equality without order", values, containsInAnyOrder(expected.toArray())); } </code></pre>
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    1. POCompare two XML strings ignoring element order
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    1. COwhat is doc equal to ?
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    2. COthe xml dom; i load it using:DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance(); DocumentBuilder builder = factory.newDocumentBuilder(); InputSource is = new InputSource(new StringReader(xml)); return builder.parse(is);
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    3. COthis is ok, just change the set to list, i didnt say it's a set
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